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以下是有关汉诺塔问题的程序段 , 若在 main 函数中有调用语句 hanoi(3,'A','B',' C '); 则符合程序段运行结果的选项是 void mow(char getone,char putone) { printf(''0/c– –>%c\n",getone,putone); } void hanoi(int n,char one,char two,char three) { if(n= =1) move(one,three); else { hanoi(n–1,one,three,two); movc(one,three); hanoi(n–1,two,one,three); } }A.
A– –>C A– –>B C– –>B B– –>A C– –>B A– –>C A– –>B
B.
A– –>C A– –>B C– –>B A– –>C B– –>A B– –>C A– –>B
C.
A– –>C A– –>B C– –>B A– –>C B– –>A B– –>C A– –>C
D.
A– –>C A– –>B C– –>B A– –>C A– –>B B– –>C A– –>C
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