【单选题】In the illustrated circuit, us=50sin V, the active power (the average power)on a 5 Ω resistor is P1=I1.^2*R1=10 W, the active power of the resistor R2=10Ω is calculated by the equation P2=I2.^2*R2=20W...
【单选题】In the illustrated circuit, us=100cos100t V, the active power (the average power)on the load is P=UIcos φ =6W, the reactive power of the load is Q=UIsin φ =8var. We can find out that the apparent powe...