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【简答题】
已知函数f（x）=（ax 2 +bx+c）e x 在x=1处取得极小值，其图象过点A（0，1），且在点处切线的斜率为-1． （Ⅰ）求f（x）的解析式； （Ⅱ）设函数g（x）的定义域D，若存在区间[m，n]?D，使得g（x）在[m，n]上的值域也是[m，n]，则称区间[m，n]为函数g（x）的“保值区间”． （ⅰ）证明：当x＞1时，函数f（x）不存在“保值区间”； （ⅱ）函数f（x）是否存在“保值区间”？若存在，写出一个“保值区间”（不必证明）；若不存在，说明理由．
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are looking
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were looking
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have been looking
D.
had been looking
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disappointing；disappointing
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disappointed；disappointing
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that all we have to eat to live
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which we all have eaten to live
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that we all have to eat to live
D.
which we all have to eat to live
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all the same
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all the time
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all our lives
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all over the world
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