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【简答题】
(14分).以富含硫酸亚铁的工业废液为原料生产氧化铁的工艺如下(部分操作和条件略): Ⅰ.从废液中提纯并结晶出FeSO 4 ·7 H 2 O。 Ⅱ.将FeSO 4 ·7H 2 O配制成溶液。 Ⅲ.FeSO 4 溶液与稍过量的NH 4 HCO 3 溶液混合,得到含FeCO 3 的浊液。 Ⅳ.将浊液过滤,用90 ℃热水洗涤沉淀,干燥后得到FeCO 3 固体。 Ⅴ.煅烧FeCO 3 ,得到Fe 2 O 3 固体。 已知:NH 4 HCO 3 在热水中分解。 (1)Ⅰ中,加足量的铁屑除去废液中的Fe 3 + ,该反应的离子方程式是_________________。 (2)Ⅱ中,需加一定量酸,该酸最好是 。运用化学平衡原理简述该酸的作用________________________________________________________________________。 (3)Ⅲ中,生成FeCO 3 的离子方程式是___________________________________________ 若FeCO 3 浊液长时间暴露在空气中,会有部分固体表面变为红褐色,该变化的化学方程式是_______________________________________。 (4)Ⅳ中,通过检验SO来判断沉淀是否洗涤干净,检验SO的操作是__________ ________________________________________________________________________。 (5)已知煅烧FeCO 3 的化学方程式是4FeCO 3 +O 2 2Fe 2 O 3 +4CO 2 。现煅烧464.0 kg的FeCO 3 ,得到316.8 kg产品。若产品中杂质只有FeO,则该产品中Fe 2 O 3 的质量是________kg。(摩尔质量/g·mol - 1 :FeCO 3 116 Fe 2 O 3 160 FeO 72)
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