下面代码的执行结果是()。 ls = [“2020”, “20.20”, “Python”] ls.append(2020) ls.append([2020, “2020”])print(ls)
A.
[‘2020’, ‘20.20’, ‘Python’, 2020]
B.
[‘2020’, ‘20.20’, ‘Python’, 2020, [2020, ‘2020’]]
C.
[‘2020’, ‘20.20’, ‘Python’, 2020, [‘2020’]]
D.
[‘2020’, ‘20.20’, ‘Python’, 2020, 2020, ‘2020’]