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【简答题】
在平面直角坐标系xOy中,已知动点P在正比例函数y=x的图象上,点P的横坐标为m(m>0)。以点P为圆心, 为半径的圆交x轴于A、B两点(点A在点B的左侧),交y轴于C、D两点(D点在点C的上方)。点E为平行四边形DOPE的顶点(如图)。 (1)写出点B、E的坐标(用含m的代数式表示); (2)连接DB、BE,设△BDE的外接圆交y轴Q(点Q异D),连接EQ、BQ。试问线段BQ与线段EQ的长是否相等?为什么? (3)连接BC,求∠DBC-∠DBE的度数。
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