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【简答题】
已知函数 f(x)=2 3 sinωxcosωx+1-2si n 2 ωx(ω>0) ,且函数f(x)的最周期为π. (1)若 x∈(- π 6 ,π] ,求函数f(x)的单调递减区间; (2)将函数y=f(x)的图象上各点的纵坐标保持不变,横坐标缩短到原来的 1 2 ,把所得到的图象再向左平移 π 6 个单位,得到函数y=g(x)的图象,求函数y=g(x)在区间 [0, π 8 ] 上的最小值.
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