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【多选题】
全等三角形的演示有以下几种方法( )A.
利用绘制两正方形验证三角形全等
B.
旋转第三个三角形验证全等
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【简答题】当梁内按最小配箍率配置箍筋(无弯筋)时,如梁上作用有均布荷载时,梁的斜截面抗剪承载力为 ;如梁上作用有集中荷载时,梁的抗剪承载力为 。 2.对于T形、工字形梁,翼缘位于剪压区时, ( 降低,提高)梁的受剪承载力。 3.钢筋混凝土无腹筋梁发生斜拉破坏时,受剪承载力取决于 ;发生斜压破坏时,受剪承载力取决于 ;发生剪压破坏时,受剪承载力取决于 。 4.在纵筋有弯起或截断的钢筋混凝土受弯梁中,梁的斜截面...
【单选题】Recall Lucy and Melvin from Problem 35.6. Lucy's utility function is 2XL+G and Melvin's utility function is XMG where G is their expenditures on the public goods they share in their apartment and wher...
A.
9000
B.
18000
C.
8550
D.
4500
【单选题】Lucy's utility function is 2X L +G and Melvin's utility function is X M G where G is their expenditures on the public goods they share in their apartment and where XL and X M are t heir respective pri...
A.
10000
B.
20000
C.
8050
D.
5000
【简答题】十进制数 1385 转换十六进制数为( )。
【单选题】Recall Lucy and Melvin from Problem 35.6. Lucy's utility function is 2XL+G and Melvin's utility function is XMG where G is their expenditures on the public goods they share in their apartment and wher...
A.
10000
B.
20000
C.
8050
D.
5000
【简答题】技术是指在发射端和接收端分别使用多个发射天线和接收天线，使信号通过发射端与接收端的多个天线传送和接收，从而改善通信质量。
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