有以下程序 #include int fun(char s[]) { int n=0 while(*s<=′9′&&*s>=′0′) {n=10*n+*s-′0′s++} return(n) } main() { char s[10]={′6′,′1′,′*′,′4′,′*′,′9′,′*′,′0′,′*′} printf('%d/n',fun(s)) } 程序的运行结果是
A.
9
B.
61490
C.
61
D.
5
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