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【简答题】
价格折扣和折让的形式主要有现金折扣、()、功能折扣、()和折让。
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举一反三
【单选题】In Unit 2. Arriving at the airport in Seattle, the boy, now a young man, called Information Please again to find _________.
A.
she no longer worked there
B.
she didn't like his call at all
C.
she had forgotten all about him
D.
they both meant a lot to each other
【单选题】N A 代表阿伏加德罗常数,下列说法正确的是(  )
A.
0.5mol Al与足量盐酸反应转移电子数为1N A
B.
标准状况下,11.2L SO 3 所含的分子数为0.5N A
C.
0.5mol CH 4 所含的电子数为5N A
D.
46g NO 2 和N 2 O 4 的混合物含有的分子数为1N A
【单选题】N A 代表阿伏加德罗常数,下列说法正确的是
A.
0.5 mol Al 与足量盐酸反应转移电子数为1 N A
B.
标准状况下,11.2 L SO 3 所含的分子数为0.5 N A
C.
0.5 mol CH 4 所含的电子数为1 N A
D.
46 g NO 2 和N 2 O 4 的混合物含有的分子数为1 N A
【简答题】Unit5 Topic2 SectionD 预习检测 一、 根据首字母 或 汉语提示补全单词。 1. —Is Jeff the only child in his family? —No, he has an e______ brother. 2. I want to stay alone. Please don’t let a______ in. 3. Jack r______( 拒绝 ) to...
【单选题】用N A 代表阿伏加德罗常数,下列说法正确的是(   )
A.
0.5 mol Al与足量盐酸反应转移电子数为1N A
B.
标准状况下,11.2 L SO 3 所含的分子数为0.5N A
C.
0.1 mol CH 4 所含的电子数为1N A
D.
46 g NO 2 和N 2 O 4 的混合物含有的分子数为1N A
【简答题】(8分)某有机物11g完全燃烧,生成9gH 2 O和11.2LCO 2 (标准状况下), (1)求该有机物的最简式: (2)若0.5mol此有机物的质量为44g,则该有机物的分子式: 。 (3)若此有机物无酸性,1mol此有机物能与足量的金属钠反应生成标准状况下氢气22.4L,也能使溴的四氯化碳溶液褪色,此有机物中的每个碳原子上只连接一个官能团。则它可能的结构简式(写出两种) 、
【单选题】In Unit2. After the family moved to Boston, the boy ________.
A.
called Information Please again
B.
never thought of her again
C.
missed his friend deeply
D.
forgot his friend soon
【单选题】In Unit2. When the boy was young, he was amazed at an unkonwn voice in the telephone at home because_________.
A.
there was a person living in it.
B.
they had one of the first telephones.
C.
there was nothing the voice did not know
D.
people could talk over the telephone
【单选题】用N A 代表阿伏加德罗常数,下列说法正确的是 [     ]
A.
0.5mol Al与足量盐酸反应转移电子数为l N A
B.
标准状况下,11.2 L SO 3 所含的分子数为0.5 N A
C.
0.1 mol CH 4 所含的电子数为1 N A
D.
46 g NO 2 和N 2 O 4 的混合物含有的分子数为1 N A
【单选题】In Unit 2. Information Please advised the boy to ______ to stop the pain.
A.
open the fridge
B.
take out some of ice
C.
find his mother
D.
put a piece of ice on the wounded finger
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