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【简答题】
Roman soldiers in some places built long rows of signal towers. When they had a message to send, the soldiers shouted it from tower to tower. If there were enough towers and enough soldiers with loud voices, important news could be sent quickly over distance. In Africa, people learned to send messages by beating on a series of large drums ( 鼓 ). Each drum was kept within hearing distance of the next one. The drum beats were sent out in a special way that all the drummers understood. Though the messages were simple, they could be sent at great speed for hundreds of miles. In the eighteenth century, a French engineer found a new way to send short messages. In this way, a person held a flag in each hand and the arms were moved to various positions representing different letters of the alphabet ( 字母表 ). It was like spelling out words with flags and arms. Over a long period of time, people sent messages by all these different ways. However, not until the telephone was invented in America in the nineteenth century could people send speech sounds over a great distance in just a few seconds.
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【单选题】已知 u 1 =60sin(314t+90°)V , u 2 =80sin(314t)V ,则 u 1 - u 2 = (  )。
A.
u 1 - u 2 =20sin(314t)V
B.
u 1 - u 2 =-20sin(314t)V
C.
u 1 - u 2 =100sin(314t+143.1°)V
D.
u 1 - u 2 =-20sin(314t-143.1°)V
【单选题】以下可以成为窦性心动过缓发病因素的是
A.
饮酒
B.
剧烈运动
C.
高钾血症
D.
使用阿托品
E.
吸烟
【简答题】名词复数练习题 一、填入所给名词的正确形式。 1. I have two (knife)______. 2. There are many (box)______here . 3. There are many(bus)______ on the road. 4. A few(boy) _____are drawing on the wall. 5. The(child)____are playi...
【简答题】习题11-11图示电路,已知u 1 =400+100sin(3×314t)-20sin(6×314t)V,求电压u 2 。
【判断题】奥斯特洛夫斯基:“批评,这是正常的血液循环,没有它就不免有停滞和生病的现象。”
A.
正确
B.
错误
【单选题】以下可以成为窦性心动过缓发病因素的是
A.
饮酒
B.
使用维拉帕米
C.
剧烈运动
D.
吸烟
E.
阿托使用品
【单选题】广告效果评价中,( )指所有消费者中看到了所投放广告的人群比例,是第一重要指标。
A.
到达率
B.
记忆率
C.
喜欢程度
D.
影响购买意愿程度
【简答题】已知一RLC串联电路的端口电压和电流为 u(t)=[100cos(314t)+50cos(942t-30°)]V i(t)=[10cos(314t)+1.755cos(942t+θ 3 )]A 试求: 电压u的有效值,i的有效值以及电路的有功功率为
【简答题】已知u=220sin( 314t + 20°) V , i=10sin( 314t - 30°) A, u (超前/滞后)i。
【单选题】已知 u 1 =60sin(314t+90°)V , u 2 =80sin(314t)V ,则 u 1 + u 2 = (  )。
A.
u 1 + u 2 =140sin(314t)V
B.
u 1 + u 2 =100sin(314t)V
C.
u 1 + u 2 =100sin(314t+36.9°)V
D.
u 1 + u 2 =140sin(314t-36.9°)V
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