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【单选题】
用十六进制形式表示 8 位二进制整数时,需要的位数是( )(2017)
A.
1
B.
2
C.
3
D.
4
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【简答题】碳酸钠与水可形成几种化合物:Na 2 CO 3 ·H 2 O(s)、Na 2 CO 3 ·7H 2 O(s)、Na 2 CO 3 ·10H 2 O(s)。试分析在101.325kPa下,与碳酸钠水溶液和冰共存的含水盐最多可有几种?
【简答题】Assume that a 10V voltage drop occurs across an element from terminal 1 to terminal 2 and a current of 5A enters terminal 1. a) Specify the values of v and i for the polarity references shown in Fig....
【单选题】( )是指风景名胜资源集中、自然环境优美、具有一定规模和游览条件,并经县级以上人民政府审定命名、划定范围供人游览、观赏、休息和进行科学文化活动的地域。
A.
风景区
B.
景区
C.
风景名胜区
D.
旅游区
【判断题】8w位无符号二进制数可以表示的最大十进制数是256,对吗?
A.
正确
B.
错误
【多选题】在下列选项中,找出保险丝的主要功用。( )
A.
防止线路短路
B.
导电
C.
防止用电设备过载
D.
区分线路颜色
【判断题】风景名胜区是指风景名胜资源集中,环境优美,具有一定规模和范围,可供人们游览、休憩或进行科学文化活动的地区。
A.
正确
B.
错误
【简答题】已知Na 2 CO 3 (s)和H 2 O(l)可以生成如下三种水合物:Na 2 CO 3 ·H 2 O(s),Na 2 CO 3 ·7H 2 O(s)和Na 2 CO 3 ·10H 2 O(s)。试求:(1)在大气压力下,与Na 2 CO 3 水溶液和冰平衡共存的水合盐的最大值;(2)在298K时,与水蒸气平衡共存的水合盐的最大值。
【多选题】How do voltage-gated ion channels work?
A.
Voltage-gated ion channels have domains called voltage sensors that are extremely sensitive to changes in the membrane potential: changes above a certain threshold value exert sufficient electrical force on these domains to encourage the channel to switch from its closed to its open conformation.
B.
A change in the membrane potential does not affect how wide the channel is open, but instead alters the probability that it will open. Thus, in a large patch of membrane containing many molecules of the channel protein, one might find that on average 10% of them are open at any instant when the membrane is at one potential, whereas 90% are open after this potential changes.
C.
When one type of voltage-gated ion channel opens, the membrane potential of the cell can change. This in turn can activate or inactivate other voltage-gated ion channels.
D.
Such circuits, which couple the opening of ion channels to changes in membrane potential to the opening of additional ion channels, are fundamental to all electrical signaling in cells.
【多选题】How are action potentials mediated by voltage-gated cation channels?
A.
When a neuron is stimulated, the membrane potential of the plasma membrane shifts to a less negative value (that is, toward zero). If this depolarization is sufficiently large, it will cause voltage-gated Na + channels in the membrane to open transiently at the site. As these channels flicker open, they allow a small amount of Na + to enter the cell down its steep electrochemical gradient. The influx of positive charge depolarizes the membrane further (that is, it makes the membrane potential even less negative), thereby opening additional voltage-gated Na + channels and causing still further depolarization.
B.
This process continues in an explosive, self-amplifying fashion until, within about a millisecond, the membrane potential in the local region of the neuron’s plasma membrane has shifted from its resting value of about –60 mV to about +40 mV. The voltage of +40 mV is close to the membrane potential at which the electrochemical driving force for movement of Na + across the membrane is zero—that is, the effects of the membrane potential and the concentration gradient for Na + are equal and opposite; therefore Na + has no further tendency to enter or leave the cell.
C.
During an action potential, voltage-gated Na + channels do not act alone. The depolarized axonal membrane is helped to return to its resting potential by the opening of voltage-gated K + channels. These also open in response to depolarization, but not as promptly as the Na + channels, and they stay open as long as the membrane remains depolarized. As the local depolarization reaches its peak, K + ions (carrying positive charge) therefore start to flow out of the cell, down their electrochemical gradient, through these newly opened K + channels—temporarily unhindered by the negative membrane potential that normally restrains them in the resting cell. The rapid outflow of K + through the voltage-gated K + channels brings the membrane back to its resting state much more quickly than could be achieved by K + outflow through the K+ leak channels alone.
D.
Once it begins, the self-amplifying depolarization of a small patch of plasma membrane quickly spreads outward: the Na + flowing in through open Na + channels begins to depolarize the neighboring region of the membrane, which then goes through the same self-amplifying cycle. In this way, an action potential spreads outward as a traveling wave from the initial site of depolarization, eventually reaching the axon terminals.
【判断题】稳压二级管是一种特殊的二极管,它通常工作在反向击穿状态
A.
正确
B.
错误
相关题目:
【多选题】How are action potentials mediated by voltage-gated cation channels?
A.
When a neuron is stimulated, the membrane potential of the plasma membrane shifts to a less negative value (that is, toward zero). If this depolarization is sufficiently large, it will cause voltage-gated Na + channels in the membrane to open transiently at the site. As these channels flicker open, they allow a small amount of Na + to enter the cell down its steep electrochemical gradient. The influx of positive charge depolarizes the membrane further (that is, it makes the membrane potential even less negative), thereby opening additional voltage-gated Na + channels and causing still further depolarization.
B.
This process continues in an explosive, self-amplifying fashion until, within about a millisecond, the membrane potential in the local region of the neuron’s plasma membrane has shifted from its resting value of about –60 mV to about +40 mV. The voltage of +40 mV is close to the membrane potential at which the electrochemical driving force for movement of Na + across the membrane is zero—that is, the effects of the membrane potential and the concentration gradient for Na + are equal and opposite; therefore Na + has no further tendency to enter or leave the cell.
C.
During an action potential, voltage-gated Na + channels do not act alone. The depolarized axonal membrane is helped to return to its resting potential by the opening of voltage-gated K + channels. These also open in response to depolarization, but not as promptly as the Na + channels, and they stay open as long as the membrane remains depolarized. As the local depolarization reaches its peak, K + ions (carrying positive charge) therefore start to flow out of the cell, down their electrochemical gradient, through these newly opened K + channels—temporarily unhindered by the negative membrane potential that normally restrains them in the resting cell. The rapid outflow of K + through the voltage-gated K + channels brings the membrane back to its resting state much more quickly than could be achieved by K + outflow through the K+ leak channels alone.
D.
Once it begins, the self-amplifying depolarization of a small patch of plasma membrane quickly spreads outward: the Na + flowing in through open Na + channels begins to depolarize the neighboring region of the membrane, which then goes through the same self-amplifying cycle. In this way, an action potential spreads outward as a traveling wave from the initial site of depolarization, eventually reaching the axon terminals.