【单选题】The pancreatic glucokinase of a patient with MODY had a mutation replacing a leucine with a proline. The result was that the Km for glucose was decreased from a normal value of 6 mM to a value of 2.2 ...
A.
The patient ’ s enzyme requires a lower concentration of glucose to reach ½ Vmax.
B.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose <2.2 mM.
C.
The patient ’ s enzyme is faster than the normal enzyme at concentrations of glucose >2.2 mM.
D.
At near-saturating glucose concentration, the patient would need 90 to 100 times more enzyme than normal to achieve normal rates of glucose phosphorylation.
E.
As blood glucose levels increase after a meal from a fasting value of 5 to 10 mM, the rate of the patient ’ s enzyme will increase more than the rate of the normal enzyme.