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某同学进行试验探究时,欲配制1.0molL -1 Ba(OH) 2 溶液,但只找到在空气中暴露已久的Ba(OH) 2 ·8H 2 O试剂(化学式量:315)。在室温下配制溶液时发现所取试剂在水中仅部分溶解,烧杯中存在大量未溶物。 为探究原因,该同学查得Ba(OH) 2 ·8H 2 O 部分溶解度数据,见下表: 温度 283K 293K 303K 溶解度(g/100g H 2 O) 2.5 3.9 5.6 (1)烧杯中未溶物仅为BaCO 3 ,理由是 。 (2)假设试剂由大量Ba(OH) 2 ·8H 2 O和少量BaCO 3 组成,设计试验方案,进行成分检验,在答题纸上写出实验步骤、预期现象和结论。(不考虑结晶水的检验;室温时BaCO 3 饱和溶液的pH=9.6) 限选试剂及仪器:稀盐酸、稀硫酸、NaOH溶液、澄清石灰水、pH计、烧杯、试管、带气管、滴管 实验步骤 预期现象和结论 步骤1:取适量试剂于洁净烧杯中,加入足量蒸馏水,充分搅拌,静置,过滤,得滤液和沉淀。 ###### 步骤2:取适量滤液于试管中,滴加稀硫酸。 _______________________ 步骤3:取适量步骤1中的沉淀于试管中, , 连接带气管将产生的气体导入澄清石灰水中。 _______________________ ______________________ 步骤4:取步骤1中的滤液于烧杯中,______________________________ _______________________,说明该试剂中含有Ba(OH) 2 。 (3)将试剂初步提纯后,准确测定其中Ba(OH) 2 ·8H 2 O的含量。 实验如下:①配制250 mL 约0.1mol·L -1 Ba(OH) 2 ·8H 2 O溶液:准确称取w克试样,置于烧杯中,加适量蒸馏水,搅拌,将溶液转入 ,洗涤,,摇匀. ②滴定:准确量取25.00ml所配制Ba(OH) 2 溶液于锥形瓶中,滴加指示剂,将 (填“0.020”、“0.05”、“0.1980”或“1.5”)molL -1 盐酸装入50ml酸式滴定管,滴定至终点,记录数据。重复滴定2次。平均消耗盐酸Vml。 (4)室温下, (填“能”或“不能”) 配制1.0 mol·L -1 Ba(OH) 2 溶液,说明理由________________________________________________________________________________________.
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