【单选题】Which point was NOT mentioned in the interview?
A.
People often have different learning styles.
B.
Setting reachable goals should be paramount in learning.
C.
Pronunciation practice is key to improve comprehensibility.
D.
Learning is a step -by -step process.
【单选题】How many processes did Palmer point out in learning a language?
【简答题】回答下列各题: (1)在探究原电池中电极与电解质溶液之间的关系时,某同学设计了用铝片、铜片作电极,用浓硝酸作电解质溶液的原电池,则铜片为原电池的______极,铝片上的电极反应式为______. (2)通过______装置( 填“原电池”或“电解池”)可以实现如下反应: Cu+2H 2 O═Cu(OH) 2 +H 2 ↑ 该装置应以铜为______极,并可选用下列溶液中的______为电解质溶液(...
【判断题】The starting point of teaching is to stimulate students’ learning interest.
【单选题】X、Y、Z三种金属,X、Y作原电池的电极,稀硫酸为原电池的电解质溶液时,X是负极;把Y放在Z的硝酸盐溶液中,Y表面有Z析出.X、Y、Z的活动性顺序是( )
【简答题】电位法测定溶液的pH,通常以______作指示电极,______作参比电极,浸入试液中组成原电池。
【判断题】Summative assessment is customarily conducted at any point of a learning period.
【单选题】能够使反应Cu+2H 2 O=Cu(OH) 2 +H 2 ↑发生的是( )
A.
铜片作原电池的负极,碳棒作原电池的正极,氯化钠作电解质溶液
【多选题】某原电池工作时总的反应为Zn+Cu 2+ ===Zn 2+ +Cu,该原电池的组成可能是
A.
Zn为正极,Cu为负极,CuCl 2 溶液作电解质溶液
B.
Cu为正极,Zn为负极,稀H 2 SO 4 作电解质溶液
C.
Cu为正极,Zn为负极,CuSO 4 溶液作电解质溶液
D.
Fe为正极,Zn为负极,CuCl 2 溶液作电解质溶液
【简答题】下图各装置中(电解质溶液均为硫酸),不能构成原电池的是