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生产基地图片
B.
详情页细节图
C.
好评截图
D.
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【简答题】One cold night, I was growing sick of my life in San Francisco.There I was walking home around one o’clock in the morning after a 1 practice at the theatre. With the opening night only a week away, I ...
【单选题】临床上溶栓治疗的靶点是:
A.
凝血酶
B.
纤维蛋白溶解酶
C.
血小板析出
D.
纤维蛋白析出
【多选题】整定串级控制系统主、副调节器的参数方法有哪些?()
A.
主、副过程的时间常数相差不大,主、副回路的动态联系比较密切的情况,采用逐步逼近整定法
B.
当主、副过程时间常数相差较大时,可采用两步整定法
C.
先根据副过程的特性或经验确定副调节器的参数,然后再按单回路控制系统的整定方法一步完成主调节器的参数整定
D.
直接按单回路控制系统的整定方法整定调节器的参数
【单选题】下面程序如果只有一个错误,那么是(每行程序前面的数字表示行号)__ 1 main() 2 { 3 float a[3]={3*0}; 4 int i; 5 for(i=0;i<3;i++) scanf(“%d”,&a[i]); 6 for(i=1;i<3;i++) a[0]=a[0]+a[i]; 7 printf(“%d\n”,a[0]); 8 }
A.
第3行有错误
B.
第7行有错误
C.
第5行有错误
D.
没有错误
【单选题】下面程序如果只有一个错误,那么是(每行程序前面的数字表示行号) 。 1 main() 2 { 3 float a[3]={3*0}; 4 int i; 5 for(i=0;i<3;i++)scanf(“%f”,&a[i]); 6 for(i=1;i<3;i++)a[0]=a[0]+a[i]; 7 printf(“%d\n”,a[0]); 8 }
A.
第 3 行有错误
B.
第 7 行有错误
C.
第 5 行有错误
D.
没有错误
【简答题】One cold night, I was growing sick of my life in San Francisco.There I was walking home around one o’clock in the morning after a 31 practice at the theatre. With the opening night only a week away, I...
【单选题】Choose the best answer to complete each of the following sentences. The staff in the kitchen has _____________ the message that a customer wanted a special dish.
A.
received
B.
ordered
C.
accepted
D.
pointed
【简答题】根据短文内容和所给汉语提示,写出短文空白处各单词的正确形式。每空限填一词。 The Natural Park was set up many years ago. It lies in the _ 小题1: _ ( 南方的)part of our country. It is said that__小题2:__ (数百万)of people go there every year. But for...
【多选题】Government grants should normally be accounted on accruals basis. Which of the following grants received would you not account rather on a receipts basis?
A.
A.received in the form of land for a business to re-locate to a deprived area.
B.
B.received to enhance the literacy and communicational ability of staff
C.
received by a charity to operate one of its identified activities
D.
received to make good past losses to keep the business from closure
【多选题】加密校验和是一种有效的完整性控制方法,下面哪些句子正确说明了这种加密方法?
A.
可以查错,但不能保护数据
B.
将文件分成小块,对每一块计算 CRC 校验值
C.
只要运用恰当的算法,这种完整性控制机制几乎无法攻破
D.
计算量大并且昂贵,只适用于那些对完整性保护要求极高的情况
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