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【简答题】
设函数 ，曲线y=f（x）在点（2，f（2））处的切线方程为y=3， （Ⅰ）求f（x）的解析式； （Ⅱ）证明：函数y=f（x）的图像是一个中心对称图形，并求其对称中心； （Ⅲ）证明：曲线y=f（x）上任一点的切线与直线x=1和直线y=x所围三角形的面积为，并求出此。
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