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【简答题】
已知抛物线y=ax 2 +bx+2与x轴相交于点A（x 1 ，0），B（x 2 ，0）（x 1 ＜x 2 ），且x 1 ，x 2 是方程x 2 -2x-3=0的两个实数根，点C为抛物线与y轴的交点。 （1）求a，b的值； （2）分别求出直线AC和BC的解析式； （3）若动直线y=m（0＜m＜2）与线段AC，BC分别相交于D，E两点，则在x轴上是否存在点P，使得△DEP为等腰直角三角形？若存在，求出点P的坐标；若不存在，说明理由。
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in that
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where
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went for
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made use of
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looked out
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A.
of
B.
towards
C.
with
D.
for
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was
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had been
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has been
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A.
of
B.
towards
C.
with
D.
for