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Directions: There are 20 incomplete sentences here. For each sentence there are four choices marked A, B, C and D. Choose the ONE answer that best completes the sentence. 1. The couple are very of their adopted daughter and take good care of her. A fond B find C found D fun 2. Because he was tall and strong we found it quite easy to him. A recognizing B had recognized C recognize D recognizes 3. The height of boys aged from 10 to 16 has risen in China. A behind B movie C certain D average 4. It ought to be noticed that we are still a bit some other countries in computer science and technology. A behind B movie C certain D average 5. To make friends is not easy, and to look for a good is even more difficult. A companion B distance C design D experiment 6. These doctors are busy with a new cure for brain cancer. A experiment B experimenting C have experimented D had experimented 7. For those who have smoked for years, to stop smoking is very hard. A certain B certainty C uncertain D certainly 8. Soon after it was translated into Chinese, Harry Potter became a (an) book among children. A popular B empty C ordinary D familiar 9. There were many clothes on the wall at her home. A hang B hangs C hanging D hung 10. In order to attract customers, the restaurants on that street provide various sorts of free . A services B boats C income D arrival 11. She opened the next room which had stood for months. She thought that this room should be fine for her guests. A popular B empty C ordinary D familiar 12. When she was at home, she was to go to the United States, but when she was there, she just wanted to go back. A popular B department C service D eager 13. Bad weather delayed our and we felt sorry for our friends waiting at the station. A income B survive C arrival D department 14. He was considered as a in the field of earth science. A pioneer B boat C income D service 15. He is , friendly and patient, and gets along well with others. A gentle B obvious C necessary D negative 16. It is human nature not to feel comfortable with advice. A gentle B obvious C necessary D negative 17. Parents don’t always know what to take with children who only want to play. A kitchen B approach C appearance D defeat 18. We cheered in a loud voice when our team the other team at last. A inside B insist C defeated D defeat 19. I was cooking in the when the doorbell rang. A approach B appearance C kitchen D progress 20. It is to include the study of cultures of English-speaking countries in our learning program. A gentle B obvious C necessary D negative
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【单选题】在Excel中除第一行外,清单中的每一行被认为是数据的
A.
字段
B.
字段名
C.
标题行
D.
记录
【单选题】已知:(1)Zn(s)+ 1 2 O 2 (g)=ZnO(s)△H=-348.3kJ?mol -1 (2)4Ag(s)+O 2 (g)=2Ag 2 O(s)△H=-62.0kJ?mol -1 则Zn(s)+Ag 2 O(s)=Zn O(s)+2Ag(s)△H 等于(  )
A.
-379.3kJ?mol -1
B.
-317.3kJ?mol -1
C.
-332.8kJ?mol -1
D.
317.8kJ?mol -1
【单选题】已知: (1)Zn(s)+ O 2 (g)=== ZnO(s),ΔH= -348.3 kJ·mol -1 , (2)2Ag(s)+  O 2 (g)=== Ag 2 O(s),ΔH= -31.0 kJ·mol -1 , 则Zn(s)+ Ag 2 O(s) === ZnO(s)+ 2Ag(s)的ΔH等于 [     ]
A.
-317.3 kJ·mol -1
B.
-379.3 kJ·mol -1
C.
-332.8 kJ·mol -1
D.
317.3 kJ·mol -1
【单选题】《无线通信设备安装工程》预算定额用于拆除天、馈线及室外基站设备时,定额规定的人工调整系数为 ( )。
A.
0.7
B.
0.4
C.
1.1
D.
1.0
【单选题】已知:(1)Zn(s)+1/2O 2 (g)=ZnO(s) △H=-348.3kJ·mol -1 2Ag(s)+1/2O 2 (g)=Ag 2 O(s) △H=-31.0kJ·mol -1 则Zn(s)+Ag 2 O(s)=ZnO(s)+2Ag(s)的△H等于 [     ]
A.
-317.3kJ·mol -1
B.
-379.3kJ·mol -1
C.
-332.8kJ·mol -1
D.
+317.3kJ·mol -1
【单选题】《无线通信设备安装工程》预算定额用于拆除天、馈线及室外基站设备时,定额规定的人工调整系数为( )。
A.
0.7
B.
0.4
C.
1.1
D.
1
【单选题】链传动张紧的目的是( )。 A.使链条产生初拉力,以使链传动能传递运动和功率 B.使链条与轮齿之问产生摩擦力,以使链传动能传递运动和功率 C.避免链条垂度过大时产生啮合不良 D .避免打滑
A.
使链条产生初拉力,以使链传动能传递运动和功率
B.
使链条与轮齿之问产生摩擦力,以使链传动能传递运动和功率
C.
避免链条垂度过大时产生啮合不良
D.
D .避免打滑
【单选题】链传动张紧的目的是 ()。 A.使链条产生初拉力以使链传动能传递运动和功率 B.避免打滑 C.使链条与轮齿之间产生摩擦力,以使链传动能传递运动和功率 D.避免链条垂度过大时产生啮合不良
A.
使链条产生初拉力以使链传动能传递运动和功率
B.
避免打滑
C.
使链条与轮齿之间产生摩擦力,以使链传动能传递运动和功率
D.
避免链条垂度过大时产生啮合不良
【单选题】轮滑运动的健身功能有:有利于身体热量消耗、加大心肺机能承载、有利于肌肉之强化与发展、有利于改善身体( )的作用。
A.
体质
B.
机制
C.
健康
D.
指标
【单选题】已知: (1)Zn(s)+1/2O 2 (g)===ZnO(s) ΔH=-348.3 kJ/mol (2)2Ag(s)+1/2O 2 (g)===Ag 2 O(s) ΔH=-31.0 kg/mol 则Zn与Ag 2 O 反应生成ZnO和Ag的热化学方程式为 [     ]
A.
Zn(s)+Ag 2 O(s)===ZnO(s)+2Ag(s) ΔH=317.3 kJ/mol
B.
Zn+Ag 2 O===ZnO+2Ag ΔH=317.3 kJ/mol
C.
Zn(s)+Ag 2 O(s)===ZnO(s)+2Ag(s) ΔH=-317.3 kJ/mol
D.
2Zn(s)+2Ag 2 O(s)===2ZnO(s)+4Ag(s) ΔH=-317.3 kJ/mol
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