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【简答题】
Warmth at Midnight Canberra winters are extremely cold, and 2014 brought some of our coldest days. One weekday night I walked to the 1____ ( ) supermarket before it closed at midnight. As I approached I noticed a group of six or seven people 2____ ( ) by the supermarket entrance. Aware of the 3____ ( ) of late-night walking, I made sure I paid attention. The scene ahead looked unusual. And unusual it was. Expecting to see a group of 4____ ( ) troublemakers, I found a weak, well-dressed old man distributing items of food to a group of homeless people. Rather than just feeding them, he was also engaging them in a 5____ ( ) of warm discussion. The homeless people were rough-looking and 6____ ( ) dressed. But they listened to the man 7____ ( ), not just with gratitude for the food they had been 8____ ( ). With on charity vehicle in sight, this old man was only representing himself. After I finished shopping, the group was still there, food 9____ ( ), but all laughing. If a weak old can give to others in the 10____ ( )cold at midnight, what excuse do we have? A. dangers ( ) B. local ( ) C. happy ( ) D. reading ( ) E. freezing ( ) F. attentively ( ) G. potential ( ) H. sitting ( ) I. poorly ( ) J. given ( ) K. consumed ( ) L. circle ( )
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【简答题】We learn from Paragraph l that [A] ESPN has its offices around the world [B] all chairs in Beardsley ' s class were taken away [C]ockey is a popular sport in New York [D] Beardsley ' s course on hocke...
【单选题】货物不包括亏舱的积载因数是指每一吨货物所占的_________. (39806:第一章_船舶与货物:274)
A.
货舱容积
B.
量尺体积
C.
实际体积
D.
以上都对
【单选题】在下列多元酸或混合酸中,用NaOH标准溶液滴定时出现两个滴定突跃的是( )
A.
H 2 S (K a1 =1.3´10 - 7 , K a2 =7.1´10 - 15 )
B.
H 2 C 2 O 4 (K a1 = 5.9´10 - 2 , K a2 = 6.4´10 - 5 )
C.
H 3 PO 4 (K a1 =7.6´10 - 3 ,K a2 =6.3´10 - 8 ,K a3 =4.4´10 - 13 )
D.
HCl + 氯乙酸(K a =1.4 ´ 10 - 3 )
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A.
货舱容积
B.
量尺体积
C.
实际体积
D.
以上都对
【多选题】创业过程中的融资缺口主要存在于()之间。
A.
学术支持
B.
商业支持
C.
仅凭个人兴趣所做的研究判断
D.
基于市场潜力的商业判断
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A.
融资缺口
B.
研究缺口
C.
信息和信任缺口
D.
资源缺口
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A.
H2S ( K a1=9.1×10 - 8 K a2=1.2×10 - 15 )
B.
H2C2O4 ( K a1=5.9×10 - 2 K a2 =6.4×10 - 5 )
C.
H3PO4 ( K a1=7.5×10 - 3 K a2=6.2×10 - 8 K a3=2.2×10 - 13 )
D.
C6H4(COOH)2 ( K a1=1.3×10 - 3 K a2=2.9×10 - 6)
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A.
遵循着原理、布局、用笔、赋色等方面展开学习
B.
由浅入深,由易到难的程序,有条不紊的展开学习
C.
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D.
学习过程中的不同阶段,作不断的调整
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