The circuit is shown in the figure, the value of the resistor RL is variable. When the resisitor RL equals to _______Ω,the maximum power that the load RL can get should be equal to ________W. If the value is nor integral value, we should keep 1 decimal place after decimal point. We can use Thevenin theorem to make this circuit a simple loop circuit consisted of an open circuit voltage Uoc , the equivalent resistor Roc and the load resistor RL, when RL=Roc, we can get the maximum power. Pmax= Uoc.^2/(4*Roc)