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【简答题】
对下列句子的画线部分提问。 1. My favorite subject is history . _____ is _____ favorite subject? 2. Jeff likes P.E. because it is relaxing . _____ _____ Jeff like P.E.? 3. Mrs Jones usually eats breakfast at seven-thirty. _____ _____ does Mrs Jones usually _____ breakfast? 4. Bob wants to join the chess club. _____ _____ does Bob want to join? 5. His father can play the violin. _____ can his father _____? 6. My favorite actor is Zhou Runfa. _____ is _____ favorite actor? 7. Mary's birthday is September first. _____ _____ Mary's birthday? 8. His cousin is three years old. _____ _____ is his cousin? 9. Her new pen is two yuan. _____ _____ is her new pen? 10. He eats carrots for dinner. _____ _____ he eat for dinner?
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【单选题】坚持以人为本,要做到发展为了人民、发展依靠人民、( )。
A.
发展成果由统治阶层享受
B.
发展成果由人民共享
C.
发展成果由贡献大的人群分享
D.
发展成果由全体国民共享
【判断题】在设置薪酬时,企业需要考虑员工的期望,这符合薪酬设计的灵活原则。
A.
正确
B.
错误
【多选题】空客系列飞机中,还在使用的机型包括( )
A.
空客A300飞机
B.
客A320系列飞机
C.
客A330飞机
D.
客A340飞机
E.
客A380飞机
【单选题】Which statement below best describes a Karnaugh map?
A.
Karnaugh maps provide a graphic approach to simplifying Boolean expressions.
B.
Variable complements can be eliminated by using Karnaugh maps.
C.
A Karnaugh map can be used to replace Boolean rules.
D.
The Karnaugh map eliminates the need for using NAND and NOR gates.
【判断题】防盗瓶盖不属于片剂的安全包装( )
A.
正确
B.
错误
【单选题】承包经营权人不享有以下哪种权利( )
A.
占有,使用,收益权
B.
自主经营不受他人意志组织的权利
C.
流转权
D.
出让权
【判断题】Don't care terms are always zeros in a Karnaugh map.
A.
正确
B.
错误
【单选题】Adjacent cells on a Karnaugh map differ from each other by
A.
one variable
B.
two variables
C.
three variables
D.
answer depends on the size of the map
【单选题】Which statement below best describes a Karnaugh map?
A.
Karnaugh maps provide a graphic approach to simplifying Boolean expressions.
B.
Variable complements can be eliminated by using Karnaugh maps.
C.
A Karnaugh map can be used to replace Boolean rules.
D.
The Karnaugh map eliminates the need for using NAND and NOR gates.
【单选题】A Karnaugh map ________.
A.
gives an overall picture of how the signals flow through the logic circuit.
B.
produces the simplest sum-of-products expression
C.
provides a means of reducing complex Boolean expressions.
D.
allows any circuit to be implemented with just AND and OR gates
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