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【简答题】
已知函数f（x）=|x-m|，不等式f（x）≤3 的{x|-1≤x≤5} （Ⅰ）实数m值； （Ⅱ）若a 2 +b 2 +c 2 =1且f（2x-1） +f(2x+1)＞a+b+ 2 c 对任意实数a，b，恒成立，求实数x的取值范围．
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