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【多选题】
产品结果无论有形还是无形,其共性表现在( )
A.
市场畅销
B.
满足人们某种需要
C.
投入一定资源
D.
经过变换实现
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【简答题】碳酸钠与水可形成几种化合物:Na 2 CO 3 ·H 2 O(s)、Na 2 CO 3 ·7H 2 O(s)、Na 2 CO 3 ·10H 2 O(s)。试分析在101.325kPa下,与碳酸钠水溶液和冰共存的含水盐最多可有几种?
【多选题】风景名胜区是指( )。
A.
资源集中
B.
自然环境优美
C.
具有一定规模和游览条件
D.
经县级以上人民政府审定命名、规划范围
E.
供人们游览、观光、休息
【简答题】在一次晚会上,大家围着飞镖游戏前.只见靶子设计成如图形式.已知从里到外的三个圆的半径分别为1,2,3,并且形成A,B,C三个区域.如果飞镖没有停落在最大圆内或只停落在圆周上,那么可以重新投镖. (1)分别求出三个区域的面积; (2)雨薇与方冉约定:飞镖停落在A、B区域雨薇得1分,飞镖落在C区域方冉得1分.你认为这个游戏公平吗?为什么?如果不公平,请你修改得分规则,使这个游戏公平.
【单选题】What is wrong with the following statement about sensitivity ?( )
A.
The bigger wheel is used for a coarse adjustment to calibrated values. The smaller wheel is used for fine-adjust to calibrated values.
B.
The "Volts/Div."wheels amplify an input signal so that for a division a given voltage level is in valid.
C.
The "Time/Div."wheel determines, how long the electronic beam which draws the curve needs for moving from the left to the right edge of a division.
D.
The sensitivity of y axis controls the "time scale".
【多选题】风景名胜区是指()和进行科学文化活动的地域
A.
资源集中
B.
自然环境优美
C.
具有一定规模和游览条件
D.
经县级以上人民政府审定命名、规划范围
E.
供人们游览、观光、休息
【简答题】在一次晚会上,大家围着飞镖游戏前。只见靶子设计成如图形式。已知从里到外的三个圆的半径分别为l,2,3,并且形成A,B,C三个区域。如果飞镖没有停落在最大圆内或只停落在圆周上,那么可以重新投镖。 (1)分别求出三个区域的面积; (2)雨薇与方冉约定:飞镖停落在A、B区域雨薇得1分,飞镖落在C区域方冉得1分。你认为这个游戏公平吗? 为什么? 如果不公平,请你修改得分规则,使这个游戏公平。
【多选题】在下列选项中,找出保险丝的主要功用。( )
A.
防止线路短路
B.
导电
C.
防止用电设备过载
D.
区分线路颜色
【多选题】风景名胜区是指()和进行科学文化活动的地域
A.
资源集中
B.
自然环境优美
C.
具有一定规模和游览条件
D.
县级以上人民政府审定命名规划范围
E.
供人们游览观光休息
【判断题】条码的编码方法是指条码中条、空的编码规则以及二进制的逻辑表示的设置。
A.
正确
B.
错误
【多选题】How are action potentials mediated by voltage-gated cation channels?
A.
When a neuron is stimulated, the membrane potential of the plasma membrane shifts to a less negative value (that is, toward zero). If this depolarization is sufficiently large, it will cause voltage-gated Na + channels in the membrane to open transiently at the site. As these channels flicker open, they allow a small amount of Na + to enter the cell down its steep electrochemical gradient. The influx of positive charge depolarizes the membrane further (that is, it makes the membrane potential even less negative), thereby opening additional voltage-gated Na + channels and causing still further depolarization.
B.
This process continues in an explosive, self-amplifying fashion until, within about a millisecond, the membrane potential in the local region of the neuron’s plasma membrane has shifted from its resting value of about –60 mV to about +40 mV. The voltage of +40 mV is close to the membrane potential at which the electrochemical driving force for movement of Na + across the membrane is zero—that is, the effects of the membrane potential and the concentration gradient for Na + are equal and opposite; therefore Na + has no further tendency to enter or leave the cell.
C.
During an action potential, voltage-gated Na + channels do not act alone. The depolarized axonal membrane is helped to return to its resting potential by the opening of voltage-gated K + channels. These also open in response to depolarization, but not as promptly as the Na + channels, and they stay open as long as the membrane remains depolarized. As the local depolarization reaches its peak, K + ions (carrying positive charge) therefore start to flow out of the cell, down their electrochemical gradient, through these newly opened K + channels—temporarily unhindered by the negative membrane potential that normally restrains them in the resting cell. The rapid outflow of K + through the voltage-gated K + channels brings the membrane back to its resting state much more quickly than could be achieved by K + outflow through the K+ leak channels alone.
D.
Once it begins, the self-amplifying depolarization of a small patch of plasma membrane quickly spreads outward: the Na + flowing in through open Na + channels begins to depolarize the neighboring region of the membrane, which then goes through the same self-amplifying cycle. In this way, an action potential spreads outward as a traveling wave from the initial site of depolarization, eventually reaching the axon terminals.
相关题目:
【多选题】How are action potentials mediated by voltage-gated cation channels?
A.
When a neuron is stimulated, the membrane potential of the plasma membrane shifts to a less negative value (that is, toward zero). If this depolarization is sufficiently large, it will cause voltage-gated Na + channels in the membrane to open transiently at the site. As these channels flicker open, they allow a small amount of Na + to enter the cell down its steep electrochemical gradient. The influx of positive charge depolarizes the membrane further (that is, it makes the membrane potential even less negative), thereby opening additional voltage-gated Na + channels and causing still further depolarization.
B.
This process continues in an explosive, self-amplifying fashion until, within about a millisecond, the membrane potential in the local region of the neuron’s plasma membrane has shifted from its resting value of about –60 mV to about +40 mV. The voltage of +40 mV is close to the membrane potential at which the electrochemical driving force for movement of Na + across the membrane is zero—that is, the effects of the membrane potential and the concentration gradient for Na + are equal and opposite; therefore Na + has no further tendency to enter or leave the cell.
C.
During an action potential, voltage-gated Na + channels do not act alone. The depolarized axonal membrane is helped to return to its resting potential by the opening of voltage-gated K + channels. These also open in response to depolarization, but not as promptly as the Na + channels, and they stay open as long as the membrane remains depolarized. As the local depolarization reaches its peak, K + ions (carrying positive charge) therefore start to flow out of the cell, down their electrochemical gradient, through these newly opened K + channels—temporarily unhindered by the negative membrane potential that normally restrains them in the resting cell. The rapid outflow of K + through the voltage-gated K + channels brings the membrane back to its resting state much more quickly than could be achieved by K + outflow through the K+ leak channels alone.
D.
Once it begins, the self-amplifying depolarization of a small patch of plasma membrane quickly spreads outward: the Na + flowing in through open Na + channels begins to depolarize the neighboring region of the membrane, which then goes through the same self-amplifying cycle. In this way, an action potential spreads outward as a traveling wave from the initial site of depolarization, eventually reaching the axon terminals.