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【简答题】
Ravi, like many project 1 , had studied the waterfall model of software development as the primary software life-cycle 2 . He was all set to use it for an upcoming project, his first assignment. However, Ravi found that the waterfall model could not be used because the customer wanted the software delivered in stages, something that implied that the system had to be delivered and built in 3 and not as 4 . The situation in many other projects is not very different. The real world rarely presents a problem in which a standard process, or the process used in a previous project, is the best choice. To be the most suitable, an existing process must be 5 to the new problem. A development process, even after tailoring, generally cannot handle change requests. To accommodate change requests without losing control of the project, you must supplement the development process with a requirement change management process.
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举一反三
【简答题】下面程序段的运行结果是( )_. int main(){ int i,t,a[10]={25,40,29,8,17,6,15,4,3,2}; t=a[0]; for(i=0;i<10;i++) if(a[i]A. 29 B. 40 C. 15
【单选题】糖原在脱枝酶催化下生成的重要产物
A.
葡萄糖
B.
6—磷酸果糖
C.
1-磷酸果糖
D.
1-磷酸葡萄糖
E.
5-磷酸葡萄糖
【简答题】下面程序段的运行结果是( )_. int main(){ int i,t,a[10]={25,40,29,8,17,6,15,4,3,2}; t=a[0]; for(i=0;i<10;i++) if(a[i]A. 29 B. 40 C. 15 D. 2
【单选题】下面程序段的运行结果是 int main() { int i,t,a[10]={25,40,29,8,17,6,15,4,3,2} ; t=a[0]; for(i=0;i<10;i ++ ) if( a[i]
A.
2
B.
3
C.
25
D.
8
【单选题】下面程序段的运行结果是( )。 int main() { int i,t,a[10]={25,40,29,8,17,6,15,4,3,2}; t=a[0]; for(i=0;i<10;i++) if(a[i] printf("%d\n",t); return 0; }
A.
29
B.
40
C.
15
D.
2
【单选题】糖原在脱枝酶催化下生成的重要产物是()。
A.
葡萄糖
B.
6—磷酸果糖
C.
1-磷酸果糖
D.
1-磷酸葡萄糖
E.
5-磷酸葡萄糖
【判断题】若两直线斜率不等,则它们中斜率大的其倾斜角大.
A.
正确
B.
错误
【简答题】下面程序段的运行结果是 _ _ _______ 。 int main() { int i,t,a[10]={25,40,29,8,17,6,15,4,3,2} ; t=a[0]; for(i=0;i<10;i ++ ) if( a[i]
【多选题】某机械厂锻造车间噪声很大,作业人员由于长时间接触高分贝噪声,导致听阈升高。为降低对作业人员的职业病危害,该厂应采取的工程措施有( )。
A.
升级改造设备,将普通齿轮改为有弹性轴套的齿轮,减弱噪声源
B.
采用减震、隔振、隔声等措施,以及安装消音器等,控制声源辐射
C.
优化工艺流程,将锻打改为摩擦压力加工,降低噪声发射功率
D.
配发并督促作业人员规范佩戴护耳器,如耳塞、耳罩、防声盔
E.
每两年对作业人员进行一次听力检测,把听力显著降低的人调离噪声环境
【单选题】#include int main( ) { int i,t,a[10]={25,40,29,8,17,6,15,4,3,2}; t=a[0]; for(i=0;i<10;i++) if(a[i]
A.
29
B.
40
C.
15
D.
2
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