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【单选题】
第2 题中的 caller 函数对应的机器级代码如下: 1 pushl %ebp 2 movl %esp, %ebp 3 subl $24, %esp 4 movl $100, -12(%ebp) 5 movl $200, -8(%ebp) 6 movl -8(%ebp), %eax 7 movl %eax, 4(%esp) 8 movl -12(%ebp), %eax 9 movl %eax, (%esp) 10 call add 11 movl %eax, -4(%ebp) 12 movl -4(%ebp), %eax 13 leave 14 ret 假定 caller 的调用过程为 P ,对于上述指令序列,以下叙述中错误的是( )。A.
第 2 条指令使 BEP 内容指向 caller 栈帧的底部
B.
从上述指令序列可看出， caller 函数没有使用被调用者保存寄存器
C.
第 1 条指令将过程 P 的 EBP 内容压入 caller 栈帧
D.
第 3 条指令将栈指针 ESP 向高地址方向移动，以生成当前栈帧
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