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【单选题】
从键盘任意输入a，b，c的值，编程计算并输出下面一元二次方程的根【图片】当a=0时，输出“该方程不是一元二次方程”，当a≠0时，分三种情况计算并输出方程的根，即：【图片】,两个不相等的，分别为：x1 = p+q，x2 = p-q【图片】,两个相等的为：x1 = x2 =p【图片】,一对共轭复根，分别为：x1 = p+qi，x2 = p-qi按要求在空白处填写适当的表达式或语句，使程序完整并符合题目要求。#include #include #include #defineEPS1e-6intmain(){floata,b,c,disc,p,q;printf("Pleaseenterthecoefficientsa,b,c:");scanf("%f,%f,%f",&a,&b,&c);if(________)/*a=0时，输出“不是二次方程”*/{printf("Itisnotaquadraticequation!\n");exit(0);}disc=b*b-4*a*c;/*计算判别式*/p=-b/(2*a);q=sqrt(fabs(disc))/(2*a);if(___________)/*判别式等于0时，输出两相等*/{printf("x1=x2=%.2f\n",p);}else{if(__________)/*判别式大于0时，输出两不等*/{printf("x1=%.2f,x2=%.2f\n",p+q,p-q);}else/*判别式小于0时，输出两共轭复根*/{printf("x1=%.2f+%.2fi,",p,q);printf("x2=%.2f-%.2fi\n",p,q);}}return0;}
A.
第11行： fabs(a) <= EPS 第20行： fabs(disc) <=EPS 第26行： disc> EPS
B.
第11行： fabs(a) = 0 第20行： fabs(disc) = 0 第26行： disc > EPS
C.
第11行： fabs(a) = 0 第20行： fabs(disc) <= EPS 第26行： disc>= 0
D.
第11行： fabs(a) <= EPS 第20行： fabs(disc)=0 第26行： disc>= EPS
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