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4 Chris Jones is Managing Director of Supaserve, a medium-sized supermarket chain faced with intense competition from larger competitors in their core food and drink markets. They are also finding it hard to respond to these competitors moving into the sale of clothing and household goods. Supaserve has a reputation for friendly customer care and is looking at the feasibility of introducing an online shopping service, from which customers can order goods from the comfort of their home and have them delivered, for a small charge, to their home. Chris recognises that the move to develop an online shopping service will require significant investment in new technology and support systems. He hopes a significant proportion of existing and most importantly, new customers, will be attracted to the new service. Required: (a) What bases for segmenting this new market would you recommend and what criteria will help determine whether this segment is sufficiently attractive to commit to the necessary investment? (10 marks)
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【判断题】课文《都江堰》选自余秋雨《文化苦旅》
A.
正确
B.
错误
【多选题】测量误差的主要来源包括外界条件、观测者自身条件和( )。
A.
测量方法
B.
测量仪器
C.
测量者视力
D.
测量时间
E.
测量位置
【判断题】经过几年的迅速发展,众筹已经逐步形成股权制众筹、募捐制众筹、借贷制众筹和奖励制众筹等多种运营模式。
A.
正确
B.
错误
【单选题】若有以下定义和语句,则输出结果是( )。 char *sp="\t\b\\\0English\n"; printf("%d",strlen(sp));
A.
 12
B.
 3
C.
 17
D.
 13
【单选题】若有以下定义,则能打印出字母M的语句是( )。struct person{ char name[12]; int num;};struct person class[8]={"Linan",20,"zhanghai",18,"Maming",23,"wanghua",25,"chenqi",17};
A.
printf("%c",class[3].name);
B.
printf("%c",class[3].name[1]);
C.
printf("%c",class[2].name[1]);
D.
printf("%c",class[2].name[0]);
【单选题】石灰砂浆粉刷的墙面出现空鼓、起泡的现象,是由( )引起的
A.
欠火石灰
B.
过火石灰
C.
正火石灰
D.
石膏
【判断题】产生测量误差的原因包括观测者感觉器官的不完善和测量技能的 高低、仪器制作不完善和外界条件的影响等几个因素。
A.
正确
B.
错误
【判断题】余秋雨 1992 年出版《文化苦旅》,名声大噪,家喻户晓,大文化散文或文化散文就此命名。
A.
正确
B.
错误
【判断题】产生测量误差的原因包括观测者感觉器官的限制和测量技能的高低、仪器制作不完善和外界条件的影响等几个因素。
A.
正确
B.
错误
【单选题】若有以下定义 , 输出字母 M 的语句是 : 。 struct person { char name[9]; int age; }; struct person st[10] = {{"john",17},{"paul",19},{"Mary",18}};
A.
printf("%c",st[2].name);
B.
printf("%c",st[3].name[1]);
C.
printf("%c",st[2].name[1]);
D.
printf("%c",st[2].name[0]);
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