【单选题】程序功能:输入 n 的值( n<10 ),计算 1!+2!+3!+......+n! ,并输出计算结果。 #include int main() { int i, n; long sum=0,fac=1; //fac 存储每个加项(阶乘)的值 printf(" 请输入 n 的值: "); scanf(" %d",&n); for( i=1; i<=n; i++)...
【简答题】// 【E6_6.c】 求和1!+2!+3!+4!+...10! #include #include void main() { int num; // num = 1~10 int fac; //存放每一个n的阶乘 int sum = 0; //存放和值 int n; for(num=1; num=1) { fac = fac * n; n = 【空2】; } sum = 【空3】; ...
【简答题】______is a relatively complex form. of compounding in which a new word is formed by joining the initial part of one word and the final part of another word. For example, the English word smog is made ...