皮皮学,免费搜题
登录
搜题
【简答题】
下列选项中说法不准确的是() ① 保密性是指网络信息不被泄露给非授权的用户、实体或过程 ② 完整性是指信息未经授权不能改变的特性 ③ 可用性是指信息可被任何用户访问的特性 ④ 不可抵赖性也称作为不可否认性,在应用系统的交互过程中,确信参与者的真实同一性 A. ① B. ③ C. ④ D. ③④
拍照语音搜题,微信中搜索"皮皮学"使用
参考答案:
参考解析:
知识点:
.
..
皮皮学刷刷变学霸
举一反三
【简答题】已知函数 f(x)= ax-1 x+1 ,  其中 a∈R . (1)当a=1时,求函数满足f(x)≤1时的x的集合; (2)求a的取值范围,使f(x)在区间(0,+∞)上是单调减函数.
【简答题】已知a∈R,函数f(x)=x|x-a|. (Ⅰ)当a=2时,求使f(x)≥x成立的x的集合; (Ⅱ)求函数y=f(x)在区间[1,2]上的最小值.
【判断题】他汀类降脂药主要降低甘油三酯
A.
正确
B.
错误
【简答题】已知定义在R上的奇函数f(x).当x<0时,f(x)=x 2 +2x. (Ⅰ)求函数f(x)的解析式; (Ⅱ)问:是否存在实数a,b(a≠b),使f(x)在x∈[a,b]时,函数值的集合为 [ 1 b , 1 a ] ?若存在,求出a,b;若不存在,请说明理由.
【简答题】已知a∈R,函数f(x)=x 2 |x-a|, (Ⅰ)当a=2时,求f(x)=x使成立的x的集合; (Ⅱ)求函数y=f(x)在区间[1,2]上的最小值。
【简答题】已知a∈R,函数f(x)=x 2 |x-a|. (Ⅰ) 当a=1时,求使f(x)=x成立的x的集合; (Ⅱ) 判断函数y=f(x)的奇偶性; (Ⅲ)当a>2时,求函数y=f(x)在区间[1,2]上的最小值.
【简答题】已知函数f(x)=x|x 2 -a|,a∈R. (Ⅰ)当a≤0时,求证函数f(x)在(-∞,+∞)上是增函数; (Ⅱ)当a=3时,求函数f(x)在区间[0,b]上的最大值.
【单选题】Finally, they return the()to the people who bought shares in the company.
A.
cost
B.
price
C.
profits
【单选题】Zwick Company bought 80,000 shares of the voting common stock of Handy Corporation in January 2013. In December, Handy announced $200,000 net income for 2013 and declared and paid a cash dividend of $...
A.
$0.
B.
$28,000.
C.
$56,000.
D.
None of the above is correct.
【单选题】A 'trade debtor' of a company can best be described as a person or firm who______.
A.
bought goods from the company on credit and has not yet paid
B.
borrowed money from the company in the form. of a loan
C.
sold goods on credit to the company and has not been paid
D.
made a loan to the company
相关题目: