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【简答题】
f（x）=x 2 -x+b，且f（log 2 a）=b，log 2 f（a）=2（a≠1）， （1）求f（log 2 x）的最小值； （2）当x取，f（log 2 x）＞f（1）且log 2 [f（x）]=＜f（1）．
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