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【简答题】
设a∈R,函数f(x)=ax 3 -2x 2 -4ax, (1)若x=2是函数y=f(x)的极值点,求a的值; (2)在(1)的条件下,求函数f(x)在区间[-1,5]上的最值. (3)是否存在实数a,使得函数f(x)在R上为单调函数,若是,求出a的取值范围,若不是,请说明理由.
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A.
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devote to
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add to
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stick to
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