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【简答题】
某配位化合物为深蓝色晶体，由原子序数依次增大的A、B、C、D、E五种元素组成，其原子个数比为l4:4:5:1:1。其中C、D元素同主族且原子序数D为C的二倍，E元素的外围电子排(n-1)d n+6 ns l ，回答下列问题。 （1）元素B、C、D的第一电离能的由大到小排列顺序为 。(用元素符号表示) （2）D元素原子的最外层电子排 。 （3）该配位化合物的化学式为 ，配体的中心原子的杂化 。 （4）C元素可与A元素形成两种常见的化合物，其原子个数比分别为1：1和l：2，两种化合物可任意比互溶，解释其主要原因为 。 （5）A元素与B元素可形成分子式为A 2 B 2 的某化合物，该化合物的分子具有平面结构，则其结构式为 ，分子中含有 个s键， 个p键。 （6）A元素与E元素可形成一种红色化合物，其晶体结构单元如图。则该化合物的 化学式为 。该化合物可在氯气中燃烧，生成一种棕黄色固体和一种气体，写出该反应的化学方程式 。
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