代码题: c++ int a[101][101]; int b[101][101]; int m, n; cin >> m >> n; for (int i = 1; i <= m; i++) for (int j = 1; j <= n; j++) { cin >> a[i][j]; } double count = 0; double k = 0; for (int i = 1; i <= m; i++) for (int j = 1; j <= n; j++) { cin >> b[i][j]; if (b[i][j] == a[i][j]) count++; k++; } cout<
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