编程,求s=1+3+5+...19。 A. s=0; for n=1:10 xiang=2*n-1; s=s+xiang; end B. s=0; for n=1:10 xiang=2*n+1; s=s+xiang; end C. s=0;n=1; while n<=19 s=s+n; n=n+2; end; D. s=0;n=1; while n<=19 s=s+n*2-1; n=n+2; end;
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【单选题】______ he once felt like giving up, he now has the determination to push further and keep on going.