已知在1×10 5 Pa,298 K条件下,2 mol氢气燃烧生成水蒸气放出484 kJ热量,下列热化学方程式正确的是
A.
H 2 O ( g ) = H 2 ( g ) + 1/2O 2 ( g )△H =' +242' kJ/mol
B.
2H 2 ( g ) + O 2 ( g ) = 2H 2 O ( l )△H = -484 kJ/mol
C.
H 2 ( g ) + 1/2O 2 ( g ) = H 2 O ( g )△H =' +242' kJ/mo
D.
2H 2 ( g ) + O 2 ( g ) = 2H 2 O ( g )△H =' +484' kJ/mol