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【单选题】
患者,男,43岁,反复食欲减退,乏力4年,加重伴皮肤巩膜1个月。近1感腹胀明显,尿黄。查体:精神萎靡,皮肤巩膜深度,可见蜘蛛痣、肝掌。注射部位有瘀斑,腹膨隆,肝脾未扪及,移动性浊音阳性。ALT120U/L,白蛋白28g/L,球蛋白35g/L,总胆468µmol/L,凝血酶原活动度(PTA)28%;HBsAg(+),抗HBe(+),抗HBc(+)。该患者最可能的诊断是(  )
A.
急性重症肝炎
B.
亚急性重症肝炎
C.
慢性重型肝炎
D.
慢加急性重型肝炎
E.
淤胆型肝炎
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【单选题】Look at the following writing question and choose which essay structure is incorrect . Some people think that governments should spend money on railways. Others believe that there should be more inves...
A.
(1) introduction; (2) body paragraph 1; (3) body paragraph 2; (4) conclusion
B.
(1) introduction; (2) body paragraph; (3) conclusion
C.
(1) introduction; (2) body paragraph 1; (3) body paragraph 2; (4) body paragraph 3; (5) conclusion
【简答题】已知函数f(x)=x 2 +(a+1)x+lg|a+2|(a∈R,且a≠-2). (Ⅰ)若f(x)能表示成一个奇函数g(x)和一个偶函数h(x)的和,求g(x)和h(x)的解析式; (Ⅱ)命题P:函数f(x)在区间[(a+1) 2 ,+∞) 上是增函数; 命题Q:函数g(x)是减函数.如果命题P、Q有且仅有一个是真命题,求a的取值范围; (Ⅲ)在(Ⅱ)的条件下,比较f(1)和 1 6 的大小.
【简答题】短文填词。 (1)O Sundays, we like (2)g to the movies. My (3)f movies are (4)t . Some people think they're scary but I like (5)t very much. I don't like (6)d because they are boring. But some people like the...
【简答题】设a∈R,f(x)为奇函数,且 f(2x)= a? 4 x - a -2 4 x +1 (1)试求f(x)的反函数f -1 (x)的解析式及f -1 (x)的定义域; (2)设 g(x)=lo g 2 1+x k ,是否存在实数k,使得对于任意的 x∈[ 1 2 , 2 3 ] ,f -1 (x)≤g(x)恒成立,如果存在,求实数k的取值范围.如果不存在,请说明理由.
【简答题】如图,在矩形ABCD中,AB=12cm,BC=6cm.点E、 F分别在AB、CD上,将矩形ABCD沿EF折叠,使点A、 D分别落在矩形ABCD外部的点A 1 、D 1 处,则整个阴影部分图形的周长为(        )。
【简答题】已知函数 f(x)=lo g a 1-x 1+x (0<a<1) . (1)求函数f(x)的定义域D,并判断f(x)的奇偶性; (2)如果当x∈(t,a)时,f(x)的值域是(-∞,1),求a与t的值; (3)对任意的x 1 ,x 2 ∈D,是否存在x 3 ∈D,使得f(x 1 )+f(x 2 )=f(x 3 ),若存在,求出x 3 ;若不存在,请说明理由.
【判断题】行星及行星的卫星的分布是有规律的,行星与太阳的距离和规则卫星离中心行星的距离均服从提丢斯-玻德定则。
A.
正确
B.
错误
【简答题】Everybody dreams. Some people think dreams can tell us about the future. Other people think dreams tell us about ourselves. It's like our 1 is talking to us. Why are dreams often strange and hard to u...
【单选题】如图,在矩形ABCD中,AB=12cm,BC=6cm,点E、F分别在AB、CD上,将矩形ABCD沿EF折叠,使点A、D分别落在矩形ABCD外部的点A′、D′处,则整个阴影部分图形的周长为(  )
A.
18cm
B.
36cm
C.
40cm
D.
72cm
【简答题】已知:如图,矩形ABCD中AB:BC=5:6,点E在BC上,点F在CD上,EC= 1 6 BC,FC= 3 5 CD,FG⊥AE与G.求证:AG=4GE.
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