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【单选题】
为获得较好的混合状态,同时避免结晶的破碎,可采用气体混合方式,或利用直径或叶片较大的搅拌桨,( )桨的转速。
A.
升高
B.
降低
C.
不变
D.
不确定
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举一反三
【单选题】当归四逆汤所治厥逆的病机是
A.
肝郁气滞
B.
阳气内郁不达四末
C.
元气大亏,阳气欲脱
D.
血虚寒凝,阳气不得温煦四末
【单选题】Jim ___________ a maths class now. [     ]
A.
 has
B.
 have
C.
 having
D.
 is having
【单选题】米氏常数km的物理意义是:
A.
当酶促反应速率达到最大反应速率四分之一时的底物浓度。
B.
当酶促反应速率达到最大反应速率一半时的底物浓度。
C.
当酶促反应速率达到最大反应速率四分之三时的底物浓度。
D.
当酶促反应速率达到最大反应速率时的底物浓度。
【简答题】简述米氏常数Km的物理意义。
【单选题】The child is neither old enough nor clever enough to realize the _________ action on his own.
A.
desired
B.
desirable
【判断题】Chinese think no possible gain is achieved by having the child struggle to put a key into box since the child is neither old enough nor clever enough.
A.
正确
B.
错误
【简答题】...since the child is neither old enough nor clever enough to realize the desired action on his own, what possible gain is achieved by having him struggle?
【单选题】The child is _______ clever that she won't ______ your trick.
A.
so ; fall into
B.
so ; fall for
C.
such ; fall over
D.
such ; fall into
【简答题】... since the child is neither old enough nor clever enough to realize the desired action on his own, what possible gain is achieved by having him struggle?
【单选题】当归四逆汤所治厥逆的病机是
A.
肝郁气滞
B.
阳气内郁不达四末
C.
元气大亏,阳气善脱
D.
肾阳衰微,阴阳之气不相须接
E.
血虚寒凝,阳气不得温煦四末
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