皮皮学,免费搜题
登录
搜题
【简答题】
Man is called by nature to live in society; for he needs many things which are necessary to his life, and which by himself he cannot procure for himself. Whence it follows that man naturally becomes part of a group, to procure him the means of living well.He needs this assistance for two reasons.First, in order that he may obtain the elementary necessities of life; this he does in the domestic circle of which he is a part. Every man receives from his parents life and nourishment and education; and the reciprocal aid of the family members facilitates the mutual provision of the necessities of life. But there is a second reason why the individual is helped by the group of which he is a part, and in which alone he finds his adequate well-being. And this is, that he may not only live, but live the good life---which is enabled by the opportunities of social intercourse. Thus civil society aids the individual in obtaining the material necessities, by uniting in the same city a great number of crafts, which could not be so united in the same family. And civil society also assists him in the moral life. What does the word assistance most probably mean in the text?
拍照语音搜题,微信中搜索"皮皮学"使用
参考答案:
参考解析:
知识点:
.
..
皮皮学刷刷变学霸
举一反三
【判断题】本期增加发生额-本期减少发生额=本期期末余额-本期期初余额。
A.
正确
B.
错误
【简答题】程序如下: main() { int i=4; printf('%d',-++i); } 该程序执行后的输出结果以及i的值分别是______ 、_______。
【单选题】以下关于对称,不正确的叙述是:()
A.
平面中的点对称可以通过环形阵列实现。
B.
平面中的轴对称可以通过“ROTATE”命令实现。
C.
平面中的轴对称可以通过“MIRRIOR”命令来实现。
D.
三维中的平面对称可以通过三维镜像来实现。
【单选题】以下关于对称,不正确的叙述是():
A.
平面中的点对称可以通过环型阵列实现。
B.
平面中的轴对称可以通过矩形阵列实现。
C.
平面中的轴对称可以通过“MIRRIOR”命令实现。
D.
三维中的平面对称可以通过三维镜像实现。
【判断题】胆固醇在胆汁液中沉积,则易形成胆结石。( )
A.
正确
B.
错误
【单选题】下列选项属于线缺陷的是 。
A.
空位
B.
间隙原子
C.
位错
D.
亚晶界
【多选题】以下那些事乐器
A.
笛子
B.
钢琴
C.
架子鼓
D.
桌子
【简答题】欢乐颂的那些事 安迪、曲筱绡、樊胜美、邱莹莹、关雎尔是欢乐颂电视剧中的五美,请大家查阅资料,思考以下问题: 1欢乐颂五美你最喜欢哪个?为什么 2在职场中,公司最喜欢的职场个性是五美当中的哪个? 3你如何让你最喜欢的这个人物在职场中变得更有干劲?
【单选题】以下关于对称,不正确的叙述是(  )。
A.
平面中的点对称可以通过环形阵列实现。
B.
平面中的轴对称可以通过“ROTATE”命令实现。
C.
平面中的轴对称可以通过“MIRRIOR”命令来实现。
D.
三维中的平面对称可以通过三维镜像来实现。
【单选题】账户余额的计算公式是()
A.
期末余额=上期期初余额+本期减少发生额-本期增加发生额
B.
期末余额=上期期初余额+本期增加发生额-本期减少发生额
C.
期末余额=期初余额+本期增加发生额-本期减少发生额
D.
期末余额=期初余额+本期减少发生额-本期增加发生额
相关题目: