已知函数f(x)= 1 3 x 3 + 1-a 2 x 2 -ax-a,x∈R,其中a>0. (1)求函数f(x)的单调区间; (2)若函数f(x)在区间(-2,0)内恰有两个零点,求a的取值范围; (3)当a=1时,设函数f(x)在区间[t,t+3]上的最大值为M(t),最小值为m(t).记g(t)=M(t)-m(t),求函数g(t)在区间[-3,-1]上的最小值.
【简答题】The skies are raining big blocks of ice, and experts are trying to learn what’s going on. For the second time in six days, California was attacked by ice balls. The latest happened on early Thursday. ...