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【单选题】
Choose the most suitable heading from the list a-d for paragraph 4
A.
The shellfish have a long history in the rock and many different kinds are known.
B.
The first animals with true backbones were the fishes, first known in the rocks of 375 million years ago. About 300 million years ago, the amphibians, the animals able to live both on land and in water, appeared. They were giant, sometimes 8 feet long, and many of them lived in the swampy pools in which our coal seam, or layer, or formed. The amphibians gave rise to the reptiles and for nearly 150 million years, these were the principal forms of life on land, in the sea, and in the air.
C.
The earliest animals whose remains have been found were all very simple kinds and lived in the sea. Later forms are more complex, and among these are the sea-lilies, relations of the starfishes, which had long arms and were attached by a long stalk to the sea bed, or to rocks.
D.
When an animal dies, the body, its bones, or shell, may often be carried away by streams into lakes or the sea and there get covered up by mud. If the animal lived in the sea its body would probably sink and be covered with mud. More and more mud would fall upon it until the bones or shell become embedded and preserved.
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【判断题】图示RLC串联电路,S闭合前的谐振频率与品质因数为 f0与Q, S闭合后的谐振频率与品质因数为 与 Q ',则 ,Q < Q '。____
A.
正确
B.
错误
【简答题】假定(DX)=10111001B,(CL)=3,(CF)=1,试确定下列各条指令单独执行后,DX中的值。 (1)SHR DX,1 (2)RCR DL,1 (3)RCL DX,CL
【单选题】下面各组中的两个比可以组成比例的是(  )
A.
7:5 和8:6
B.
10:9和0.2:1.8
C.
1 12 : 1 8 和6:4
D.
0.6:1.2和 4 5 :1.6
【简答题】假定(DX)=10111001B,(CL)=3,(CF)=1,试确定下列各条指令单独执行后,DX中的值。 (1)SHR DX,1 DX=( ) (2) RCR DL,1 DX=( ) (3)RCL DX,CL DX=( )
【简答题】解方程. 20-1.2x=5.6 1 2 x:x= 3 5 : 6 7 .
【简答题】关于《大清新刑律》,下列哪一选项是错误的?( )
【判断题】090178 图示 RLC 串联电路, S 闭合前后的谐振角频率与品质因数分别为 w 0 、 Q 与 w 0 ' 、 Q ' ,则 w 0 > w 0 ' , Q> Q ' 。
A.
正确
B.
错误
【单选题】假定DX=10111001B,CL=3,CF=1,则执行指令SHL DX,CL后,DX的值为( )。
A.
005CH
B.
0017H
C.
1700H
D.
05C8H
【判断题】图示 RLC 串联电路, S 闭合前的谐振频率与品质因数为 f 0 与 Q , S 闭合后的谐振频率与品质因数为 与 Q ' ,则 , Q Q ' 。( )
A.
正确
B.
错误
【简答题】直接写出得数. 1.25×8= 十.1+6.7= 1 2 - 1 十 = 十.02-1.2= 0.u2÷0.6= 6 u × 2 十 = 7 25 ÷ 2 5 = 十200×0=
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