【单选题】( )和横向柱列构成横向平面排架,是厂房的基本承重结构。
【简答题】下面程序运行后输出结果中的最后一行是______。 #include int main() { int i, j,b[3][3]= {0} ; for(i=0; i<3; i++) { for(j=0; j<3; j++) switch(i-j+2) { case 0: case 1: b[i][j]=1;break; case 2: b[i][j]=2;break; case 3: b[i...
【判断题】在对方发球时,应首先准备接发球,然后再换位,避免造成接发球混乱。
【单选题】In your test database, you have created the ORDERS table as an index-organized table (IOT). To facilitate faster querying, you have created a mapping table and a bitmap index on the ORDER_FILLED colum...
A.
Export and import the mapping table.
B.
Drop and re-create the mapping table.
C.
Truncate the mapping table and reinsert the values.
D.
Use the ALTER TABLE .. REBUILD command to defragment the mapping table.
【单选题】In your test database, you have created the ORDERS table as an index-organized table (IOT). To facilitate faster querying, you have created a mapping table and a bitmap index on the ORDER_FILLED colum...
A.
export and import the mapping table
B.
drop and re-create the mapping table
C.
truncate the mapping table and reinsert the values
D.
use the ALTER TABLE···REBUILD command to defragment the mapping table
【单选题】In your test database, you have created the ORDERS table as an index/x7forganized table (IOT). To facilitate faster querying, you have created a mapping table and a bitmap index on the ORDER_FILLED co...
A.
export and import the mapping table
B.
drop and recreate the mapping table
C.
truncate the mapping table and reinsert the values
D.
use the ALTER TABLE .. REBUILD command to defragment the mapping table
【简答题】下面程序运行后输出结果中的最后一行是 # include int main( ) { int a[3][3], b[3 * 3]={1, 2} , i, j; for(i=2; i<3* 3; i++) b[i]=b[i-1]+b[i-2]; for(i=0; i<3; i 十十 ) for(j=0; j<3; j++) a[j][i]=b[i* 3+j]; for(i=0; i<3; i++ )...
【简答题】下面程序运行后输出结果中的最后一行是 # include int main( ) { int i, j,b[3][3]={0}; for(i=0; i<3; i 十 +) { for(j=0; j<3; j++) switch(i-j+2) { case 0: case 1: b[i][j]=l;break; case 2: b[i][j]=2 ;break; case 3: b[i][j]=3 ...
【简答题】下面程序运行后输出结果中的最后一行是______。 #include int main() { int a[3][3], b[3*3]={1, 2},i,j; for(i=2;i<3*3;i++) b[i]=b[i-1]+b[i-2]; for(i=0; i<3;i++) for(j=0; j<3;j++) a[j][i]=b[i*3+j]; for(i=0;i<3;i++) { for(j=0...