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【单选题】
《怒沉百宝箱》的作者是?
A.
濛初
B.
干宝
C.
D.
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参考解析：
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【单选题】在窗体上画两个命令按钮，名称分别为Command1、Command2，并编写如下程序 Const n=5,m=4 Dim a(m,n) Private Sub Command1_Click() k=1 For i=1 To m Forj=1 To n a(i,j)=k k=k+1 Next j Next i End Sub Private Sub Command2_Click() summ=0 F...
A.
计算矩阵外围一圈元素的累加和
B.
计算矩外围一圈以外的所有元素的累加和
C.
计算矩阵第1列和最后—列元素的累加和
D.
计算矩阵第1行和最后—行元素的累加和
查看完整题目与答案
【单选题】The reasons for writing a report don't include ( ).
A.
keeping a formal and complete record
B.
being circulated to a number of people or referred to
C.
making it easy to find the right person to account for the content
D.
simplify the work process
查看完整题目与答案
【单选题】下列有关组稿的表述中,不准确的是( )。
A.
组稿是落实选题计划的基本途径
B.
组稿是保证稿源连续性的重要条件
C.
组稿是开发选题的主要方法
D.
组稿是组织作者队伍的主要手段
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【单选题】盐酸和内因子由下列哪种细胞分泌
A.
主细胞
B.
壁细胞
C.
内分泌细胞
D.
杯状细胞
E.
颈黏膜液细胞
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【判断题】整体而言,项目是一个不断完善的过程。
A.
正确
B.
错误
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【单选题】Whatever _____ the reasons for it,we cannot tolerate this disloyalty.
A.
were
B.
have been
C.
 be
D.
are
查看完整题目与答案
【单选题】不属于真核生物启动子特点的是
A.
分为I、II、III类
B.
与之结合的RNA聚合酶不只一种
C.
转录因子辅助启动子与RNA聚合酶相结合
D.
5S rRNA编码基因的转录由I类启动子控制
E.
II类启动子可调控大部分snRNA编码基因的转录
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【单选题】有如下程序： #include using namespace std class Base { private: void funl() const{cout$amp protected: void fun2() const{cout$amp public: void fun3() const{cout$amp } class Derived:protected Base { public: v...
A.
． ①②③④
B.
． ①②③
C.
． ②③④
D.
． ①④
查看完整题目与答案
【单选题】Which are not the reasons why the soap opera suddenly becomes 'in'?
A.
Because the viewers want to be happy and enjoy themselves.
B.
Because soap opera makes young people feel close to their people.
C.
Because the viewers can find themselves in the soap opera characters.
D.
Because the young people have to bear the responsibilities for their troubles.
查看完整题目与答案
【单选题】有如下程序: Const n = -5 Const m = 6 Dim a(n To m) As Integer For i = LBound(a, 1) To UBound(a, 1) a(i) = i Next i Print a(LBound(a, 1)); a(UBound(a, 1)) 运行后输出的结果为( )。
A.
0  0
B.
-5  0
C.
-5  6
D.
0  6
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相关题目：
【单选题】在窗体上画两个命令按钮，名称分别为Command1、Command2，并编写如下程序 Const n=5,m=4 Dim a(m,n) Private Sub Command1_Click() k=1 For i=1 To m Forj=1 To n a(i,j)=k k=k+1 Next j Next i End Sub Private Sub Command2_Click() summ=0 F...
A.
计算矩阵外围一圈元素的累加和
B.
计算矩外围一圈以外的所有元素的累加和
C.
计算矩阵第1列和最后—列元素的累加和
D.
计算矩阵第1行和最后—行元素的累加和
查看完整题目与答案
【单选题】The reasons for writing a report don't include ( ).
A.
keeping a formal and complete record
B.
being circulated to a number of people or referred to
C.
making it easy to find the right person to account for the content
D.
simplify the work process
查看完整题目与答案
【单选题】下列有关组稿的表述中,不准确的是( )。
A.
组稿是落实选题计划的基本途径
B.
组稿是保证稿源连续性的重要条件
C.
组稿是开发选题的主要方法
D.
组稿是组织作者队伍的主要手段
查看完整题目与答案
【单选题】盐酸和内因子由下列哪种细胞分泌
A.
主细胞
B.
壁细胞
C.
内分泌细胞
D.
杯状细胞
E.
颈黏膜液细胞
查看完整题目与答案
【判断题】整体而言,项目是一个不断完善的过程。
A.
正确
B.
错误
查看完整题目与答案
【单选题】Whatever _____ the reasons for it,we cannot tolerate this disloyalty.
A.
were
B.
have been
C.
 be
D.
are
查看完整题目与答案
【单选题】不属于真核生物启动子特点的是
A.
分为I、II、III类
B.
与之结合的RNA聚合酶不只一种
C.
转录因子辅助启动子与RNA聚合酶相结合
D.
5S rRNA编码基因的转录由I类启动子控制
E.
II类启动子可调控大部分snRNA编码基因的转录
查看完整题目与答案
【单选题】有如下程序： #include using namespace std class Base { private: void funl() const{cout$amp protected: void fun2() const{cout$amp public: void fun3() const{cout$amp } class Derived:protected Base { public: v...
A.
． ①②③④
B.
． ①②③
C.
． ②③④
D.
． ①④
查看完整题目与答案
【单选题】Which are not the reasons why the soap opera suddenly becomes 'in'?
A.
Because the viewers want to be happy and enjoy themselves.
B.
Because soap opera makes young people feel close to their people.
C.
Because the viewers can find themselves in the soap opera characters.
D.
Because the young people have to bear the responsibilities for their troubles.
查看完整题目与答案
【单选题】有如下程序: Const n = -5 Const m = 6 Dim a(n To m) As Integer For i = LBound(a, 1) To UBound(a, 1) a(i) = i Next i Print a(LBound(a, 1)); a(UBound(a, 1)) 运行后输出的结果为( )。
A.
0  0
B.
-5  0
C.
-5  6
D.
0  6
查看完整题目与答案