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【简答题】
某固体物质由FeCl 3 、Na 2 CO 3 、BaCl 2 、Na 2 SO 4 中的一种或几种组成，为确定该固体物质的组成，进行了以下实验： （1）取适量的该物质完全溶解于水，得到无色透明溶液A； （2）向溶液A中加入过量的盐酸，生成气体，得到溶液B； （3）在溶液B中加入过量的氢氧化钡溶液，产生白色沉淀，过滤，得滤液C； （4）在滤液C中先加入过量的稀硝酸，再加入适量硝酸银溶液恰好完全反应，产生白色沉淀，过滤，得滤液D． 根据上述实验回答下列问题：． ①原固体物质是由______ 组成； ②在（3）中发生反应的化学方程式为______；（写一个） ③滤液D中含有溶质的化学式为______； ④通过上述实验可以判断原固体物质中一定不存在BaCl 2 ，理由为____________ ______．
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