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【单选题】
派的鼻祖是( )
A.
B.
C.
D.
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【简答题】有以下程序 #include void main() { char c1,c2; scanf("%d",&c1); c2=c1+9; printf("%c%c\n",c1,c2); } 若程序运行时从键盘输入48,则输出结果为
【单选题】以下程序运行时,若从键盘输入 9,则输出结果 是 ( ) 。 #inlude int main() { int a=1 ; scanf(" %d ",&a); if(a++<9) printf(" %d\n ",a); else printf(" %d\n ",a); return 0; }
A.
8
B.
9
C.
10
D.
11
【单选题】以下程序运行时,若从键盘输入9,则输出结果是_______。 main() { int a=1; scanf("%d",&a); if(a++<9) printf("%d\n",a); else printf("%d\n",a); }
A.
10
B.
11
C.
9
D.
8
【单选题】Aggregate planners seek to match supply and demand:
A.
at minimum overall cost
B.
by staying within company policy
C.
(a) and (b)
D.
keeping inventories at a minimum
E.
all of the above
【简答题】简述神经元的结构特点
【单选题】The main disadvantage(s) of informal techniques used for aggregate planning is(are):
A.
they are expensive to do
B.
they may not result in the best plan
C.
they take a long time to do
D.
they require use of a computer
E.
lack of formal education of the planners
【单选题】Accommodating peak demands and effectively using labor resources during periods of low demand would be the goal of aggregate planners in 
A.
Manufacturing
B.
Military
C.
Archeology
D.
Libraries
E.
Financial Services
【单选题】以下程序运行时,若从键盘输入9,则输出结果是_______。 #inlude main() { int a=1; scanf(" %d ",&a); if(a++<9) printf(" %d\n ",a); else printf(" %d\n ",a);
A.
10
B.
11
C.
9
D.
8
【判断题】有以下程序(说明:字符0的ASCII码值为48) #include main() {char c1,c2; scanf("%d",&c1); c2=c1+9; printf("%c%c\n",c1,c2); } 若程序运行时从键盘输入48,则输出结果为 09
A.
正确
B.
错误
【单选题】以下程序运行时,若从键盘输入9,则输出结果是( )。#includeint main(){int a=1;scanf("%d",&a);if(a++<9) printf("%d\n",a);else printf("%d\n",a);}
A.
10
B.
11
C.
9
D.
8
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