皮皮学，免费搜题
登录
搜题
【单选题】
You are developing a Windows Communication Foundation (WCF) service.One of the service operations contains the following code.private static int counter = 0;[OperationContract]public void IncrementCount（ ）{ counter++;}You need to set a service behavior that prevents two or more threads from incrementing the counter variable at the same time. Which code segment should you use to set the service behavior?（）A.
[ServiceBehavior(InstanceContextMode = InstanceContextMode.Single, ConcurrencyMode = ConcurrencyMode.Single)]
B.
[ServiceBehavior(InstanceContextMode = InstanceContextMode.PerSession, ConcurrencyMode = ConcurrencyMode.Single)]
C.
[ServiceBehavior(InstanceContextMode = InstanceContextMode.Single, ConcurrencyMode = ConcurrencyMode.Multiple)]
D.
[ServiceBehavior(InstanceContextMode = InstanceContextMode.PerCall, ConcurrencyMode = ConcurrencyMode.Reentrant)]
拍照语音搜题，微信中搜索"皮皮学"使用
参考答案：
参考解析：
知识点：
皮皮学刷刷变学霸
举一反三
【简答题】7 已知R = 10Ω,C = 2F的一阶电路,其时间常数τ =#( )#s;已知一阶RL电路的R = 10Ω,L = 2H,则其时间常数τ = #( )#s。
【多选题】根据《中华人民共和国传染病防治法》的规定，可以按甲类传染病处理的传染病有( )
A.
艾滋病
B.
传染性非典型肺炎
C.
肺炭疽
D.
人感染高致病性禽流感
E.
梅毒
【简答题】7 已知R=10Ω,C=2F的一阶电路,其时间常数τ=______________;已知一阶RL电路的R=10Ω,L=2H,则其时间常数τ=______________。