皮皮学,免费搜题
登录
搜题
【单选题】
某建设项目达到设计生产能力后,全厂定员1000人,工资和福利费按照每人每年20000元估算。每年的其他费用为1000万元,其中其他制造费600万元,现金的周转次数为每年10次。流动资金估算中应收账款估算额为2000万元,应付账款估算额为1500万元,存货估算额为6000万元,则该项目流动资金估算额为( )万元。
A.
6800
B.
6760
C.
9800
D.
9760
拍照语音搜题,微信中搜索"皮皮学"使用
参考答案:
参考解析:
知识点:
.
..
皮皮学刷刷变学霸
举一反三
【单选题】下列选项中,能填入空白处4的代码是( )
A.
int k = 0; k < cols; k++
B.
int k = 0; k
C.
int k = 0; k
D.
int k = 0; k
【简答题】某企业借得1000万元的贷款,在10年内以年利率12%等额偿还,则每年年末应付的金额为多少? (画出时间线)
【单选题】Not until they left school _____ how much their teachers loved them and helped them. [     ]
A.
they realized
B.
did they realize
C.
they would realize
D.
had they realized
【单选题】某企业借得1000万元的贷款,在10年内以年利率12%等额偿还,则每年应付的金额为( )
A.
1000/(P/A,12%,10)
B.
1000×(P/A,12%,10)
C.
1000×(A/F,12%,10)
D.
1000×(P/F,12%,10)
【简答题】#include<stdio.h> int fun(int h) {static int a[3]={1,2,3); int k; for(k=0;k<3;k++)a[k]+=a[k]-h; for(k=1;k<3;k++)printf('%d/t',a[k]); return(a[h]); } main() {int t=1;fun(fun(t));}
【判断题】非语言沟通是一种不用语言文字或符号,非口头和非书面的沟通,不可以单独存在,只能伴随书面沟通或口头沟通的方式出现。
A.
正确
B.
错误
【单选题】下面程序 main() { int a=-1,b=4,k; k=(a++<=0)&&(!(b--<=0)); printf('%d%d%d%d/n',k,a,B) ; } 的输出是_______。
A.
00 3
B.
0 1 2
C.
1 0 3
D.
1 1 2
【简答题】某企业借得 1000 万元的贷款,在 10 年内以年利率 12% 等额偿还,则每年应付的金额为多少?
【单选题】Not until they left school________how much their teachers loved them and helped them.
A.
they realized
B.
did they realized
C.
the would realized
D.
had they realized
【单选题】Not until they left school ______ how much their teachers loved them and helped them.
A.
they realized
B.
had they realized
C.
they would realize
D.
did they realize
相关题目: