皮皮学,免费搜题
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【判断题】
一般来说,市盈率高,说明投资者对该公司的发展前景看好,愿意出较高的价格购买该公司股票,但市盈率也不能说越高越好。
A.
正确
B.
错误
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皮皮学刷刷变学霸
举一反三
【单选题】下面程序段,运行后的结果是 Private Sub Commandl_Click( ) Dim b%(1 To 4),i%,t# For i=1 To 4 b(i)=i Next i t=Tof(b( ) ) Print't=';t, End Sub Function Tof(a() As Integer) Dim t#,i% t=1 For i=2 To UBound(A)t=t * a(i) ...
A.
t=18
B.
t=24
C.
t=30
D.
t=32
【单选题】The basic function of a government is ___.
A.
to provide stability
B.
to make laws and enforce laws
C.
to provide many services, such as schools, parks, sewage systems, and streets and 34 highways
D.
to regulate, or control, activities such as trade and transportation
【单选题】It can be inferred from the passage that the basic function of bodily activity in speech is to ______.
A.
make the listener feel emotional
B.
make the speaker understood
C.
strengthen the speaker's oral words
D.
convey the speaker's implied meaning to the listener
【单选题】It can be inferred from the passage that the basic function of bodily activity in speech is to ______.
A.
make the listener feel emotional
B.
make the speaker understood
C.
amplify or intensify the speaker's spoken words
D.
convey the speaker's implied meaning to the listener
【单选题】What is not the basic function of intonation?
A.
intentions
B.
emotions
C.
behaviors
D.
attitudes
【单选题】下面程序段 。 for(t=1;t<=100;t++) { scanf(“%d”,&x); if(x<0) continue; printf(“%3d”,t); }
A.
当x<0时整个循环结束< /div>
B.
x>=0 时什么也不输出
C.
printf 函数永远也不执行
D.
最多允许输出100个非负整数
【单选题】下面程序段: for(t=1;t<=100;t++) { scanf("%d",&x); if(x<0) continue; printf("%3d",t); }
A.
当x<0时,整个循环结束< /div>
B.
x>=0时,什么也不输出
C.
printf函数永远也不被执行
D.
最多允许输出100个非负整数
【单选题】The basic function of money is ( ).
A.
exchange media
B.
value storage
C.
value scale
D.
deferred payment
【单选题】The basic function of the centrifugal pump impeller is to _____.
A.
directly increase the pressure of the liquid being pumped
B.
directly increase the velocity of the liquid being pumped
C.
convert the potential energy of the liquid to kinetic energy
D.
separate air from the liquid being pumped
【简答题】下面程序段:( )for (t=1; t<=100;t++){cin>>x; if(x<0) continue; cout
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