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【简答题】
Tomorrow was his girlfriend’s birthday and the young man was having a difficult time deciding on a present for her. She already had more clothes than she knew what to do with them, so he couldn’t get any kind of apparel. She never ate sweets, so candy was out of the question. What then? He had a very special reason for wanting to impress her with just the right gift; tomorrow he was going to make an offer of marriage to her. He finally decided on perfume(香水). All girls liked perfume. That raised another problem, however. What kind did she prefer? He couldn’t ask her because that would ruin the surprise. At last the young man hit upon a brilliant idea. That afternoon, pretending to take his girlfriend’s fox terrier, a little dog for a walk, the young man and the dog went directly to the perfume counter of the town’s biggest department store. Good! There was a large array (长列) of perfume. He beckoned(招呼) a clerk, instructing her to open a large number of bottles and wave the stoppers under the dog’s nose. Nestled in the young man’s arms, the terrier began to be restless and bored as this seemingly pointless game went on. Then Fritz suddenly became frisky , wiggling in the young man’s arms and barking excitedly, as the clerk waved one stopper under its nose. “I’ll take that one,” said the young man to the clerk. The price was high, but it was worth it, he thought. “My favorite perfume!” said the delighted girl the next evening as she unwrapped the package. “How did you know?” she asked, dabbing some perfume behind each ear. “Intuition(直觉), I guess.” said the young man, deciding that it wasn’t exactly wrong to tell a lie under the circumstances. One day, after they were married, he would admit that his intuition had really been a little dog named Fritz. 小题1:Which of the following words best describes the young man in the story ? A.Kind-hearted B.Curious C.Creative D.Mean 小题2:The underlined word “frisky” in Paragraph 4 means ______. A.lively B.angry C.uneasy D.puzzled 小题3:According to the story, the birthday present for the girl was actually decided on by _____. A.the young man B.the store clerk C.the man’s intuition D.the dog Fritz 小题4:Which of the following statements is NOT TRUE ? A.The young man wanted to give his girlfriend a pleasant surprise. B.The pet dog Fritz knew what the young man wanted very well. C.The kind of perfume the young man chose was expensive. D.The young man told a white lie about his final choice of the perfume.
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【单选题】在北半球中高纬地区,通常温压场不对称的高压系统中心轴线随高度总是向:
A.
西南倾斜
B.
东南倾斜
C.
西北倾斜
D.
东北倾斜
【单选题】某种混合气体中可能含有N 2 、HCl、CO中的一种或几种,为确定该混合气体的成分,将混合气体依次通过NaHCO 3 溶液和灼热的Fe 2 O 3 ,气体体积无变化但是有黑色物质生成;再通过NaOH溶液,气体体积明显减小;将燃着的木条伸入装有剩余气体的集气瓶中,木条熄灭(假设每步反应都是完全的),则下列说法中正确的是(提示:气体的分子数之比等于体积比)
A.
一定有CO和HCl,肯定无N 2
B.
一定有CO和N 2 ,可能有HCl
C.
一定有CO和HCl,可能有N 2
D.
一定有CO和N 2 ,肯定无HCl
【单选题】某种混合气体可能含有N 2 、HCl、CO。把混合气体依次通过足量的NaHCO 3 溶液和灼热CuO,气体体积都没有变化。再通过足量的Na 2 O 2 固体,气体体积减小。最后通过灼热的铜网,经充分反应后气体体积又减小,但还有剩余气体。以下对混合气体组成的判断,正确的是(    )
A.
一定没有N 2 ,CO和HCl中至少有一种
B.
一定有N 2 、HCl和CO
C.
一定有N 2 ,CO和HCl中至少有一种
D.
一定有N 2 和HCl,没有CO
【单选题】某种混合气体,可能含有N 2 、HCl、CO.把混合气体依次通过足量的NaHCO 3 溶液和灼热的CuO,气体体积都没有变化;再通过足量的Na 2 O 2 固体,气体体积减小;最后通过灼热的铜丝,经充分反应后气体体积又减小,但还有气体剩余.以下对混合气体组分的判断中,正确是(  )
A.
一定有N 2 、HCl,没有CO
B.
一定有N 2 ,CO和HCl中至少有一种
C.
一定有N 2 、CO和HCl
D.
一定没有N 2 ,CO和HCl中至少有一种
【判断题】防止计算机病毒的措施之一是用户重视知识产权,不要使用盗版软件
A.
正确
B.
错误
【单选题】某混合气体可能含有N 2 、HCl和CO,把混合气体依次通过足量的NaHCO 3 溶液和灼热的CuO,气体的体积都没有变化。再通过足量的Na 2 O 2 固体,气体体积减小。最后通过灼热的铜网,经充分反应后气体体积又减小,但还有剩余气体。以下对混合气体组成的判断,正确的是
A.
一定没有N 2 ,CO和HCl中至少有一种
B.
一定有N 2 、HCl和CO
C.
一定有N 2 ,CO和HCl中至少有一种
D.
一定有N 2 和HCl,没有CO
【判断题】防病毒的措施之一是用户重视知识产权,不要盗版复制软件。()
A.
正确
B.
错误
【单选题】某种混合气体,可能含有N 2 、HCl和CO,把混合气体依次通过足量的NaHCO 3 溶液和灼热的CuO,气体体积都没有变化,经干燥后再通过足量的Na 2 O 2 固体,气体体积减少,最后通过灼热的铜网,经充分反应后,气体体积又减少,但还有剩余气体,以下对混合气体区分的判断,正确的是(    )
A.
一定没有N 2 ,CO和HCl中至少有一种
B.
一定没有N 2 ,CO和HCl都有
C.
一定有N 2 ,CO和HCl中至少有一种
D.
一定有N 2 和HCl,肯定没有CO
【单选题】水路改造中,PPR管采用()接管,PVC管采用()接管。
A.
热熔、胶粘
B.
胶粘、热熔
C.
热熔、热熔
D.
胶粘、胶粘
【单选题】某种混合气体,可能含有N 2 、HCl、CO。把混合气体依次通过足量的NaHCO 3 溶液和灼热的CuO,气体体积都没有变化;再通过足量的Na 2 O 2 固体,气体体积变小;最后通过灼热的铜网,经充分反应后气体体积又减小,但还有剩余气体。下列对混合气体组成的判断,正确的是 [     ]
A.
一定没有N 2 ,HCl和CO至少有一种
B.
一定有N 2 、HCl、CO
C.
一定有N 2 ,HCl和CO中至少有一种
D.
一定有N 2 与HCl,一定没有CO
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