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【单选题】
Which is the best heading for the following paragraph? Researchers like Colton don't believe it is right to measure machine creativity directly to that of humans who ‘have had millennia to develop our skills’. Others, though, are fascinated by the prospect that a computer might create something as original and subtle as our best artists. So far, only one has come close. Composer David Cope invented a program called Experiments in Musical Intelligence, or EMI. Not only did EMI create compositions in Cope’s style, but also that of the most revered classical composers, including Bach, Chopin and Mozart. Audiences were moved to tears, and EMI even fooled classical music experts into thinking they were hearing genuine Bach. Not everyone was impressed however. Some, such as Wiggins, have blasted Cope's work as pseudoscience, and condemned him for his deliberately vague explanation of how the software worked. Meanwhile, Douglas Hofstadter of Indiana University said EMI created replicas which still rely completely on the original artist’s creative impulses. When audiences found out the truth they were often outraged with Cope, and one music lover even tried to punch him. Amid such controversy, Cope destroyed EMI's vital databases.
A.
computer programs having processed genuine arts
B.
controversy arising towards computer creativity
C.
prejudice in the analyses of the audience
D.
computer creativity scared people
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【单选题】从沟通的媒介丰富性角度看,面对面交谈得分最高,它在沟通过程中传递的信息量最大,可以即时反馈。依次排列下来是( )。
A.
电子邮件、电话、备忘录和信件、广告和公告及一般文件
B.
电话、电子邮件、备忘录和信件、广告和公告及一般文件
C.
电子邮件、备忘录和信件、电话、广告和公告及一般文件
D.
电话、备忘录和信件、电子邮件、广告和公告及一般文件
【单选题】P65.下列叙述中正确的是
A.
有两个指针域的链表称为二叉链表
B.
循环链表是循环队列的链式存储结构
C.
带链的栈有栈顶指针和栈底指针,因此又称为双重链表
D.
结点中具有多个指针域的链表称为多重链表
【多选题】下列账户中,期末余额应在借方的是( )。
A.
应收账款
B.
预收账款
C.
应付账款
D.
预付账款
【判断题】当模块具有很强的凝聚力时,每个模块都应该实现多个紧密相关的功能。
A.
正确
B.
错误
【单选题】P65.属于Access域聚合函数的是
A.
Count
B.
DMax
C.
CDate
D.
Max
【简答题】18摄氏度时,已知Ba(OH)2、BaCl2、和NH4Cl无限稀释的摩尔电导率分别为0.04576、0.02406、0.01298 S∙m2∙mol-1,试求该温度时NH4∙H2O的无限稀释的摩尔电导率
【单选题】CaCl2的无限稀释摩尔电导率与其离子的无限稀释摩尔电导率的关系为:( )
A.
Λ (CaCl2)= Λ (Ca2+)+Λ (Cl-);
B.
Λ (CaCl2)=1/2Λ (Ca2+)+Λ (Cl-);
C.
Λ (CaCl2)= Λ (Ca2+)+2Λ (Cl-);
D.
以上答案均不正确
【判断题】水溶性非淀粉多糖是大、小麦中的主要抗营养因子,解决办法是添加酶制剂。
A.
正确
B.
错误
【单选题】298K 时,( NH 4 ) 2 SO 4 , NaOH 及 Na 2 SO 4 的无限稀释的摩尔电导率分别为 3.064 × 10 -2 , 2.481 × 10 -2 及 2.598 × 10 -2 S · m 2 · mol -1 ,则 NH 3 · H 2 O 的无限稀释的摩尔电导率为
A.
1.474 × 10 -2
B.
2.714 × 10 -2
C.
2.947 × 10 -2
D.
5.428 × 10 -2
【单选题】Excel12003中,在单元格中输入数字时,缺省的对齐方式是:
A.
左对齐
B.
右对齐
C.
居中对齐
D.
两端对齐
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